Explanation The mass of object is 1.00 g , the force constant of spring is 10.0 N / m , the drop in the amplitude is 25.0 % and the time is 23.1 ms . The formula to calculate natural frequency of the oscillator is, ω 0 = k m Here, k is the force constant of the spring and m is the mass of the object. Substitute 1.00 g for m and 10.0 N / m for k in above equation to find ω 0 . ω 0 = 10.0 N / m 1.00 g ( 10 − 3 kg 1 g ) = 100 s − 1 The ratio of the position for time interval t = 0 to t = 23.1 ms is, x max ( 23.1 ms ) x max ( 0 ) = 0.250 0.250 = A e − b ( 23.1 ms ) 2 m A e 0 = e − b ( 23.1 ms ) 2 m b 2 m = ln ( 0

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 15, Problem 15.82AP

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The reason for which the following situation is impossible.

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Chapter 15, Problem 15.81AP

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Chapter 15 Solutions

Physics for Scientists and Engineers, Technology Update (No access codes included)

Ch. 15 - A block on the end of a spring is pulled to...Ch. 15 - Consider a graphical representation (Fig. 15.3) of...Ch. 15 - Figure 15.4 shows two curves representing...Ch. 15 - An object of mass m is hung from a spring and set...Ch. 15 - The ball in Figure 15.13 moves in a circle of...Ch. 15 - The grandfather clock in the opening storyline...Ch. 15 - If a simple pendulum oscillates with small...Ch. 15 - You attach a block to the bottom end of a spring...Ch. 15 - A block-spring system vibrating on a frictionless,...Ch. 15 - An object-spring system moving with simple...

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The reason for which the following situation is impossible.

Solution Summary: The author explains that the following situation is impossible because no oscillation is produced. The formula to calculate the natural frequency of the oscillator is, omega

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