Concept explainers
(a)
Interpretation:
The line and wedge structure for the two enantiomers of the given allene is to be drawn.
Concept introduction:
Isomers are the compounds sharing same molecular formula but differ in the arrangements of atoms and molecules. The stereoisomer is two or more compounds that differ in the spatial arrangement of the atoms. Enantiomers are the type of stereoisomers that are non-super imposable mirror images of each other. The enantiomers exhibit same physical and chemical properties except their behavior that they show towards polarized light.
(b)
Interpretation:
The specific rotation of the other enantiomer of the given molecule is to be stated.
Concept introduction:
Those compounds which have the same molecular formula but have different spatial arrangements of atoms are known as stereoisomers.
Enantiomers are the type of stereoisomers that are non-super imposable mirror images of each other. The enantiomers exhibit same physical and chemical properties except their behavior that they show towards polarized light.
Specific rotation is an intensive property of optically active compounds. It is the ability to rotate the plain-polarized light.
Want to see the full answer?
Check out a sample textbook solutionChapter 15 Solutions
Organic Chemistry, Ebook And Single-course Homework Access
- Part II. two unbranched ketone have molecular formulla (C8H100). El-ms showed that both of them have a molecular ion peak at m/2 =128. However ketone (A) has a fragment peak at m/2 = 99 and 72 while ketone (B) snowed a fragment peak at m/2 = 113 and 58. 9) Propose the most plausible structures for both ketones b) Explain how you arrived at your conclusion by drawing the Structures of the distinguishing fragments for each ketone, including their fragmentation mechanisms.arrow_forwardPart V. Draw the structure of compound tecla using the IR spectrum Cobtained from the compound in KBr pellet) and the mass spectrum as shown below. The mass spectrum of compound Tesla showed strong mt peak at 71. TRANSMITTANCE LOD Relative Intensity 100 MS-NW-1539 40 20 80 T 44 55 10 15 20 25 30 35 40 45 50 55 60 65 70 75 m/z D 4000 3000 2000 1500 1000 500 HAVENUMBERI-11arrow_forwardTechnetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…arrow_forward
- Please correct answer and don't use hand ratingarrow_forward1. a) Assuming that an atom of arsenic has hydrogen-like atomic orbitals, sketch the radial probability plots for 4p and 4d orbitals of S atom. Indicate angular and radial nodes in these orbitals. (4 points) b) Calculate Zeff experienced by and electron in 4p AO's in a arsenic atom. Use Slater rules that were discussed in lecture. (3 points)arrow_forwardNonearrow_forward