
(a)
Interpretation:
The equilibrium constant expression for Kp and the equation that relates Kp and Kc for the equation
Concept introduction:
Equilibrium constant expression for gas-phase reactions are written using partial pressures.
PA, PB and PC are partial pressures of A, B and C gases respectively.
The concentration or partial pressure of pure solids and pure liquids are not included in the equilibrium constant expression.
The relationship between Kp and Kc is given by the following equation.
Kp = equilibrium constant in terms of partial pressure
Kc = equilibrium constant in terms of concentrations.
R = universal gas constant
T = absolute temperature
(b)
Interpretation:
The equilibrium constant expression for Kp and the equation that relates Kp and Kc for the equation
Concept introduction:
Equilibrium constant expression for gas-phase reactions are written using partial pressures.
PA, PB and PC are partial pressures of A, B and C gases respectively.
The concentration or partial pressure of pure solids and pure liquids are not included in the equilibrium constant expression.
The relationship between Kp and Kc is given by the following equation.
Kp = equilibrium constant in terms of partial pressure
Kc = equilibrium constant in terms of concentrations.
R = universal gas constant
T = absolute temperature
(c)
Interpretation:
The equilibrium constant expression for Kp and the equation that relates Kp and Kc for the equation
Concept introduction:
Equilibrium constant expression for gas-phase reactions are written using partial pressures.
PA, PB and PC are partial pressures of A, B and C gases respectively.
The concentration or partial pressure of pure solids and pure liquids are not included in the equilibrium constant expression.
The relationship between Kp and Kc is given by the following equation.
Kp = equilibrium constant in terms of partial pressure
Kc = equilibrium constant in terms of concentrations.
R = universal gas constant
T = absolute temperature

Want to see the full answer?
Check out a sample textbook solution
Chapter 15 Solutions
EBK CHEMISTRY
- Can you explain how I get these here and show the steps plz?arrow_forwardGive the IUPAC name for this compound Hydrocarbon Condensed Formulas Hint C2H5 CH2CH3 expand that in all the formula Part A: (CH3)2CHCH(C2H5)CH2CH2CH3 Give the IUPAC name for this compound. Part B: CH2=C(C2H5)CH2CH2CH3 Give the IUPAC name for this compound. Part C: (CH3)2C=CHC(C2H5)=CH2 Give the IUPAC name for this compound. Part D: CH3C=CCH(C2H5)2 Give the IUPAC name for this compound. Part E: (CH3)3CC=CCH2CH=C(CH3)2arrow_forwardSelect/ Match the correct letter from the image below for the IUPAC names given below: A B C D 3 E F G H K L Part 1. 4-methylheptane For example.mmmm Answer Letter H _for part 1 Part 2. 2,4-dimethylhexane Part 3. 2,3-dimethylpentane Part 4. 2,2-dimethylhexane Part 5. 2-ethyl-1,1,3,3-tetramethylcyclopentane Part 6. 3-ethyl-2-methylpentanearrow_forward
- Can u show the process as to how to get these?arrow_forwardSketch the expected 'H NMR spectra for the following compound. Label all of the H's in the structure and the corresponding signal for the spectra you sketch. Make sure you include the integration value and the splitting pattern for each signal Indicate how many signals you would expect in the 13C NMRarrow_forwardUse IUPAC naming rules to name the following hydrocarbon compounds: CH2-CH3 | a) CH-CH-CH2-CH-CH-CH3 b) | CH2 CH3 | CH3 CH3 \ / C=C H 1 H CH2-CH3 c) d) CH=C-CH3 e) CH3-CH2-CH2-CH=CH-CH3 f) CH2=CH-CH2-CH=CH-CH3 g) CH3-CH2-C = C-CH2-CH3 h)arrow_forward
- Q5 Name the following : a. b. C. d. e.arrow_forward25. Predict the major product of the following reaction. 1 equivalent of each of the starting materials was used. H₂C CH3 CH3 H3C H3C H3C. CH2 + H3C. heat CH3 CH H.C. CH3 H.C H.C CH3 CH CH3 CH3 A B C Earrow_forwardFind chemical structures based on the below information. a) Chemical formula C6H8O Compound is aromatic plus has two 1H NMR peaks that integrated for 3 each that are singlets (it could have more peaks in the 1H NMR b) Chemical Formula: C6H100 Compounds is conjugated 'H NMR has a signal that integrates for 6 and is a doublet IR spectra has a signal at 1730 cm-1arrow_forward
- Jaslev Propose a synthesis of the following starting from benzene and any other reagents and chemicals. No mechanisms are required. Indicate the condition for each step plus the major product for each step. More than two steps are required. Step 1 Step 2 مہد Brarrow_forwardPart C: The line formula for another branched alkane is shown below. i. In the IUPAC system what is the root or base name of this compound? ii. How many alkyl substituents are attached to the longest chain? iii. Give the IUPAC name for this compound.arrow_forwardPart D: Draw the Structural Formula for 4-ethyl-2-methylhexane Part E. Draw the Structural Formula for 1-chloro-3,3-diethylpentane (Chloro = Cl)arrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax





