CHEMISTRY  MOLECULAR NATURE OF MATTER
CHEMISTRY MOLECULAR NATURE OF MATTER
9th Edition
ISBN: 9781266177835
Author: SILBERBERG
Publisher: MCG
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Chapter 15, Problem 15.49P

(a)

Interpretation Introduction

Interpretation:

From the given compounds, compounds with higher value of solubility has to be identified and the reason for the higher value of solubility has to be explained.

The given compounds are chloroethane and methylethylamine.

Concept Introduction:

The physical properties are determined by the intermolecular forces, polarity of the compound and hydrogen bonding.  If a compound is polar and have hydrogen bonding, the solubility will be more for that compound than in non-polar compounds.

Intermolecular forces:

The forces which acts in between the atoms to hold a molecule are said to be intermolecular forces.  They are weak forces.  Intermolecular forces are categorized as hydrogen bonding, ionic bonding, ion-induced dipole forces, ion-dipole forces and Vanderwaal forces.

Hydrogen bonding:

The attraction between a lone pair of hydrogen atom with that of an electronegative atom forms hydrogen bonding.  Two water molecules are held together by hydrogen bond.

CHEMISTRY  MOLECULAR NATURE OF MATTER, Chapter 15, Problem 15.49P , additional homework tip  1

(b)

Interpretation Introduction

Interpretation:

From the given compounds, compounds with higher value of melting point has to be identified and the reason for the higher value of melting point has to be explained.

The given compounds are diethyl ether and 1-butanol.

Concept Introduction:

The physical properties are determined by the intermolecular forces, polarity of the compound and hydrogen bonding.  If a compound is polar and have hydrogen bonding, the melting point will be more for that compound than in non-polar compounds.

Intermolecular forces:

The forces which acts in between the atoms to hold a molecule are said to be intermolecular forces.  They are weak forces.  Intermolecular forces are categorized as hydrogen bonding, ionic bonding, ion-induced dipole forces, ion-dipole forces and Vanderwaal forces.

Hydrogen bonding:

The attraction between a lone pair of hydrogen atom with that of an electronegative atom forms hydrogen bonding.  Two water molecules are held together by hydrogen bond.

CHEMISTRY  MOLECULAR NATURE OF MATTER, Chapter 15, Problem 15.49P , additional homework tip  2

(c)

Interpretation Introduction

Interpretation:

From the given compounds, compounds with higher value of boiling point has to be identified and the reason for the higher value of boiling point has to be explained.

The given compounds are trimethylamine and propylamine.

Concept Introduction:

The physical properties are determined by the intermolecular forces, polarity of the compound and hydrogen bonding.  If a compound is polar and have hydrogen bonding, the boiling point will be more for that compound than in non-polar compounds.

Intermolecular forces:

The forces which acts in between the atoms to hold a molecule are said to be intermolecular forces.  They are weak forces.  Intermolecular forces are categorized as hydrogen bonding, ionic bonding, ion-induced dipole forces, ion-dipole forces and Vanderwaal forces.

Hydrogen bonding:

The attraction between a lone pair of hydrogen atom with that of an electronegative atom forms hydrogen bonding.  Two water molecules are held together by hydrogen bond.

CHEMISTRY  MOLECULAR NATURE OF MATTER, Chapter 15, Problem 15.49P , additional homework tip  3

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Chapter 15 Solutions

CHEMISTRY MOLECULAR NATURE OF MATTER

Ch. 15.4 - Prob. 15.4BFPCh. 15.4 - Prob. 15.5AFPCh. 15.4 - Prob. 15.5BFPCh. 15.4 - Prob. 15.6AFPCh. 15.4 - Prob. 15.6BFPCh. 15.4 - Prob. 15.7AFPCh. 15.4 - Prob. 15.7BFPCh. 15.6 - Prob. 15.4PCh. 15.6 - Prob. 15.5PCh. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Silicon lies just below carbon in Group 4A(14) and...Ch. 15 - What is the range of oxidation states for carbon?...Ch. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Define each type of isomer: (a) constitutional;...Ch. 15 - Prob. 15.9PCh. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - How does an aromatic hydrocarbon differ from a...Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Draw structures from the following names, and...Ch. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Determine the type of each of the following...Ch. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - Prob. 15.70PCh. 15 - Prob. 15.71PCh. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - Prob. 15.74PCh. 15 - Prob. 15.75PCh. 15 - Prob. 15.76PCh. 15 - Prob. 15.77PCh. 15 - Prob. 15.78PCh. 15 - Prob. 15.79PCh. 15 - Prob. 15.80PCh. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83PCh. 15 - Prob. 15.84PCh. 15 - Prob. 15.85PCh. 15 - Prob. 15.86PCh. 15 - Prob. 15.87PCh. 15 - What is the key structural difference between...Ch. 15 - Protein shape, function, and amino acid sequence...Ch. 15 - What linkage joins the monomers in each strand of...Ch. 15 - What is base pairing? How does it pertain to DNA...Ch. 15 - RNA base sequence, protein amino acid sequence,...Ch. 15 - Prob. 15.93PCh. 15 - Prob. 15.94PCh. 15 - Draw the structure of each of the following...Ch. 15 - Prob. 15.96PCh. 15 - Write the sequence of the complementary DNA strand...Ch. 15 - Prob. 15.98PCh. 15 - Prob. 15.99PCh. 15 - Prob. 15.100PCh. 15 - Prob. 15.101PCh. 15 - Amino acids have an average molar mass of 100...Ch. 15 - Prob. 15.103PCh. 15 - Prob. 15.104PCh. 15 - Some of the most useful compounds for organic...Ch. 15 - Prob. 15.106PCh. 15 - Prob. 15.107PCh. 15 - Prob. 15.108PCh. 15 - Prob. 15.109PCh. 15 - Prob. 15.110PCh. 15 - Prob. 15.111PCh. 15 - Prob. 15.112PCh. 15 - The polypeptide chain in proteins does not exhibit...Ch. 15 - Prob. 15.114PCh. 15 - Prob. 15.115PCh. 15 - Prob. 15.116PCh. 15 - Prob. 15.117PCh. 15 - Wastewater from a cheese factory has the following...Ch. 15 - Prob. 15.119P
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