Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 15, Problem 15.29P
To determine
Find the factor of safety
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Chapter 15 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- solve the question provided in the image.arrow_forwardDetermine the factor of safety of the slope shown in the figure below using an ESA and a TSA. The point of rotation is indicated by O and the line representing the top of the stiff soil is a tangent to the failure plane. 7 m 2 3 5m T 3 m 2 m Ysat = 18 kN/m³ 3 m Soft soil S₁ = 25 kPa = 28° Ysat = 18.5 kN/m³ Stiff soil S₁ = 70 kPa = 22°arrow_forward13.20 The slope shown in Figure 13.53 has recently failed. A geotechnical investigation indicates the failure surface was as shown. Assuming the failure occurred while undrained conditions prevailed in the slope, back-calculate the value of su. Use the Swedish slip circle method with the cross-section that existed immediately before it failed. Use y = 119 lb/ft³.arrow_forward
- The rock slope has been mapped and analysed. The data of slope geometry and rock Q1 parameters tabulated in Table 1. The face slope facing toward south and the upper slope is flatted. The discontinuity sets are as follow (dip direction / dip angle); set 1: 10/46', set 2: 190%40, and set 3: 140 /70°. Parameters Values Face slope dip angle 65° Slope height 50 meter Slope length 150 meter Unit weight of the rock 25 kN/m3 Depth of tension crack 2 m Unit weight of water 9.81 kN/m³ The cohesion of all discontinuities 50 kPa Friction angle for all discontinuities 30° ) Calculate the factor of safety for the planar failure mode when the tension crack is completely filled with water.arrow_forwardCalculate the factor of safety in terms of slope stability using the Cousin's Chart method of the soil, the information of which is given belowarrow_forwardConsider a slope given below with 10 slices, which has a circular failure surface. Each slice has 5 meters wide, and the weight of each slice was estimated on the basis of average height and a unit weight of soil ? = 16 kN/m3. The shear strength of the soil is assumed to be ? = 20 kPa and ? = 20°. The pertinent data for these ten slices is given in the table below. a) Determine the factor of safety using Janbu’s simplified method by assuming the initial ?? = ?. ?. b) Discuss how the factor of safety (stability of the Slope) will change due to the rainfall. You start to consider what environmental conditions will change first.arrow_forward
- The factor of safety (upto 2 decimal places) of an infinite soil slope shown in the figure having the properties c = 0. ф= 35°, Ydry =15 kN/m³, Ysat =19 kN/m³arrow_forwardA 45° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties Cu= 50 kN/m², qu=0° and y = 19 kN/m³ Determine the factor of safety. [Take area of wedge = 39 m²]arrow_forwardProblem 6: A cut slope is to be made as shown in the figure with the respective shear strength parameters: 0 = 29° B = 50° $ = 10° Unit weight of soil is 16 kN/m3 %3D 3.0 m Failure plane Soil cohesion = 25 kPa Height of slope = 3 m %3D Determine the factor of safety against sliding.arrow_forward
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