Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 15, Problem 15.17P
To determine
Find the factor of safety
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Sand is placed on a rock slope, as shown in Figure Q2.
(a) Show that sand will be stable (i.e., no sliding sliding) if
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Chapter 15 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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Similar questions
- A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forwardPlease answer 15.7arrow_forwardPlease answer 15.15arrow_forward
- A 30° slope has a height of 10 m as shown in the figure below. The soil in the slope has the following parameters c = 20 kPa, ϕ = 0°, γ = 18 kN/m . Calculate the factor of safety for the slip surface shown in the figure.arrow_forwardA cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?arrow_forward(Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forward
- 3. For the planar wedge shown below: 22 m Slip surface 39° 28° Calculate the factor of safety against plane failure assuming: p (degree) > (kN/m³) c (kPa) 55 2800 1850 c: cohesion of rock mass; y: unit weight of rock mass; p: friction angle of rock mass جیهان کاظیarrow_forwardPlease answer 15.14arrow_forwardA level site underlain by fully saturated clays is cut over a few days as shown in the figure below. The water table is located at the ground surface across the site. Determine the resisting moment in kN.m for the circular slip surface depicted in the Figure below shortly after excavation. Consider the soil wedge above the circular slip surface as a single free body, whose plane area is equal to 100 m2 and the centre of gravity of the soil wedge is given at Point C.arrow_forward
- Following is the variation of with depth in a granular soil deposit. A concretepile 9 m long ( in cross section) is driven into the sand andfully embedded in the sand.arrow_forwardA cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal. The Previous explorations showed that a rock layer was located at a depth of 14 m. Given that, c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.arrow_forwardA deep cut of 10 m depth is made in sandy clay for a road. The sides of the cut make an angle of 60° with the horizontal. The shear strength parameters of the soil are c' = 20 kN/m², Ø' = 25°, and y= 18.5 kN/m³. If AC is the failure plane (SEE FIGURE BELOW), estimate the factor of safety of the slope using Culmann's method. 10 m 60⁰ 40⁰ 10° c²= 20 kN/m² p' = 25° y = 18.5 kN/m³arrow_forward
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