Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
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Question
Chapter 15, Problem 15.26P
Interpretation Introduction
Interpretation:
From the given problem, the change in the indicated pH has to be calculated.
Concept introduction:
Junction potential:
Fundamental limitation on the accuracy of direct potentiometric measurements is known as junction potential.
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QUESTION: Answer Question 5: 'Calculating standard error of regression' by filling in all the empty green boxes
*The values are all provided in the first photo attached*
Draw the formula for 3-chlorobenzoic acetic anhydride.
By malonic or acetylacetic synthesis, synthesize 2-methylbutanoic acid (indicate the formulas of the compounds).
Chapter 15 Solutions
Quantitative Chemical Analysis
Ch. 15.2 - Prob. 1TYCh. 15.3 - Prob. 2TYCh. 15.6 - Prob. 3TYCh. 15.6 - Prob. 4TYCh. 15.7 - Prob. 5TYCh. 15 - Prob. 15.AECh. 15 - Prob. 15.BECh. 15 - Prob. 15.CECh. 15 - Prob. 15.DECh. 15 - Prob. 15.EE
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Prob. 15.25PCh. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Prob. 15.41PCh. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52P
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- Obtain 2-methylbutanoic acid by malonic or acetylacetic synthesis (indicate the formulas of the compounds involved).arrow_forwardEFFICIENTS SAMPLE READINGS CONCENTRATIONS Pigiadient) TOMATO SAUCE (REGULAR) TOMATO (REDUCED SALT) TOMATO SAUCE (REGULAR) TOMATO (REDUCED SALT) 58 6.274 3.898 301.7 151.2 14150 5.277 3.865 348.9 254.8 B 5.136 3.639 193.7 85.9 605 4.655 3.041 308.6 199.6 05 5.135 3.664 339.5 241.4 0139 4.676 3.662 160.6 87.6 90148 5.086 3.677 337.7 242.5 0092 6.348 3.775 464.7 186.4 PART3 5.081 3.908 223.5 155.8 5.558 3.861 370.5 257.1 4.922 3.66 326.6 242.9 4.752 3.641 327.5 253.3 50 5.018 3.815 336.1 256.0 84 4.959 3.605 317.9 216.6 38 4.96 3.652 203.8 108.7 $3 5.052 3.664 329.8 239.0 17 5.043 3.767 221.9 149.7 052 5.058 3.614 331.7 236.4 5.051 4.005 211.7 152.1 62 5.047 3.637 309.6 222.7 5.298 3.977 223.4 148.7 5.38 4.24 353.7 278.2 5 5.033 4.044 334.6 268.7 995 4.706 3.621 305.6 234.4 04 4.816 3.728 340.0 262.7 16 4.828 4.496 304.3 283.2 0.011 4.993 3.865 244.7 143.6 AVERAGE STDEV COUNT 95% CI Confidence Interval (mmol/L) [Na+] (mg/100 mL) 95% Na+ Confidence Interval (mg/100 mL)arrow_forwardIf we have two compounds: acetone (CH₃COCH₃) and acetic acid (CH₃COOH), applying heat to them produces an aldol condensation of the two compounds. If this is correct, draw the formula for the final product.arrow_forward
- If we have two compounds: acetone (CH3COCH3) and acetic acid (CH3COOH); if we apply heat (A), what product(s) are obtained?arrow_forwardQUESTION: Fill out the answers to the empty green boxes attached in the image. *Ensure you all incorporate all 27 values (per column)*arrow_forwardYou need to make a buffer by dissolving benzoic acid and sodium benzoate in water. What is the mass of benzoic acid that you would weigh out, in mg, to create 50 mL of a buffer at pH = 4.7 that will change pH no more than 0.10 units with the addition of 0.001 moles of acid or base? Enter just the answer without the units (mg) - just the number will do!arrow_forward
- Give the organic product: O A O B Ос ○ D -NH–CH3 + CH3 CH3 NEN C ? A CH3 CH3 NH- CH3 B CH3 CH3 N=N- C CH3 CH3 N=NNH CH3 D CH3 N=N CH3 NHCH3 LNH CHOarrow_forwardFinish the reaction- hand written pleasearrow_forwardGive the organic products: (benzyne) Br ? CH3 + K* :NH, liq NH3 HINT: Two products are formed. Each is a substituted aniline; they are isomers of each other. NH2 II I H₂N. CH3 CH3 III Select one: ○ A. I and II ○ B. I and III O C. I and IV O D. II and III O E. III and IV H₂N CH3 IV CH₂-NH2arrow_forward
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