Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
Question
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Chapter 15, Problem 15.2P

a)

Interpretation Introduction

Interpretation:

The missing cell potentials when Ag|AgCl and Calomel reference electrodes are saturated with KCl has to be calculated.

Concept Introduction:

Cell Voltage:

Cell voltage is the difference between cathode potential and anode potential.

Ecell=E+-E-

Where,

Ecell =cell potential

E+ =cathode potential

E- =anode potential

a)

Expert Solution
Check Mark

Answer to Problem 15.2P

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.326V .

i.e.

  • 0.523V versus S.H.E = 0.326V versus Ag|AgCl .

Explanation of Solution

Cell Voltage:

Ecell=E+-E-

Given,

E+ = 0.523V

E- = 0.00V

0.523V Versus S.H.E = x Versus Ag|AgCl .

R.H.S=L.H.S ,

R.H.S ,

Ecell=E+-E-

Ecell=0.523-0.197=0.326V

L.H.S ,

Ecell=E+-E-

Ecell=0.326V-0.00V=0.326V

So, the value of x is 0.326V .

Conclusion

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.326V .

b)

Interpretation Introduction

Interpretation:

The missing cell potentials when Ag|AgCl and Calomel reference electrodes are saturated with KCl has to be calculated.

Concept Introduction:

Cell Voltage:

Cell voltage is the difference between cathode potential and anode potential.

Ecell=E+-E-

Where,

Ecell =cell potential

E+ =cathode potential

E- =anode potential

b)

Expert Solution
Check Mark

Answer to Problem 15.2P

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.086V .

i.e.

  • -0.111V versus Ag|AgCl = 0.086V versus S.H.E .

Explanation of Solution

Cell Voltage:

Ecell=E+-E-

Given,

E+ = -0.111V

E- = 0.197V

-0.111V versus Ag|AgCl = x versus S.H.E .

R.H.S=L.H.S ,

R.H.S ,

Ecell=E+-E-

Ecell=-0.111+0.197=0.086V

L.H.S ,

Ecell=E+-E-

Ecell=0.086V-0.00 V=0.086V

So, the value of x is 0.086 V .

Conclusion

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.086V .

c)

Interpretation Introduction

Interpretation:

The missing cell potentials when Ag|AgCl and Calomel reference electrodes are saturated with KCl has to be calculated.

Concept Introduction:

Cell Voltage:

Cell voltage is the difference between cathode potential and anode potential.

Ecell=E+-E-

Where,

Ecell =cell potential

E+ =cathode potential

E- =anode potential

c)

Expert Solution
Check Mark

Answer to Problem 15.2P

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.019 V .

i.e.

  • -0.222V versus S.C.E = x versus S.H.E .

Explanation of Solution

Cell Voltage:

Ecell=E+-E-

Given,

E+ = -0.222V

E- = +0.241V

-0.222V versus S.C.E = x versus S.H.E .

R.H.S=L.H.S ,

R.H.S ,

Ecell=E+-E-

Ecell=-0.222+0.241=0.019V

L.H.S ,

Ecell=E+-E-

Ecell=0.019V-0.00 V=0.019V

So, the value of x is 0.019 V .

Conclusion

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.019V .

d)

Interpretation Introduction

Interpretation:

The missing cell potentials when Ag|AgCl and Calomel reference electrodes are saturated with KCl has to be calculated.

Concept Introduction:

Cell Voltage:

Cell voltage is the difference between cathode potential and anode potential.

Ecell=E+-E-

Where,

Ecell =cell potential

E+ =cathode potential

E- =anode potential

d)

Expert Solution
Check Mark

Answer to Problem 15.2P

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as -0.021V .

i.e.

  • 0.023V versus Ag|AgCl = -0.021V versus S.C.E .

Explanation of Solution

Cell Voltage:

Ecell=E+-E-

Given,

E+ = 0.023V

E- = +0.197V

0.023V versus Ag|AgCl = x versus S.C.E .

R.H.S=L.H.S ,

R.H.S ,

Ecell=E+-E-

Ecell=0.023+0.197=0.022V

L.H.S ,

Ecell=E+-E-

Ecell=0.022V-0.241V=-0.021V

So, the value of x is -0.021V .

Conclusion

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as -0.021V .

e)

Interpretation Introduction

Interpretation:

The missing cell potentials when Ag|AgCl and Calomel reference electrodes are saturated with KCl has to be calculated.

Concept Introduction:

Cell Voltage:

Cell voltage is the difference between cathode potential and anode potential.

Ecell=E+-E-

Where,

Ecell =cell potential

E+ =cathode potential

E- =anode potential

e)

Expert Solution
Check Mark

Answer to Problem 15.2P

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.021V .

i.e.

  • -0.023V versus S.C.E = x versus Ag|AgCl .

Explanation of Solution

Cell Voltage:

Ecell=E+-E-

Given,

E+ = -0.023V

E- = +0.241V

-0.023V versus S.C.E = x versus Ag|AgCl .

R.H.S=L.H.S ,

R.H.S ,

Ecell=E+-E-

Ecell=0.241-0.023=0.218V

L.H.S ,

Ecell=E+-E-

Ecell=0.218V-0.197V=0.021V

So, the value of x is 0.021V .

Conclusion

The missing cell potential when Ag|AgCl and Calomel reference electrodes are saturated with KCl was calculated as 0.021V .

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