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(a)
Interpretation:
The name of the given compound has to be given.
Concept Introduction:
The hydrocarbons which contain only single bonds are said to be
The Alkanes are named following some rules:
- The name of the alkane is given by the number of carbon atoms present in the chain. It is said to be Root of the alkane.
Root = number of carbon atoms in chain.
- To name the root, for one carbon atom, the root name use is meth-. For two carbon atoms, the root name is eth-, for three carbon atoms, it is prop-, for four carbon atoms, it is but-, for five carbon atoms, it is pent- and so on.
- The root name is followed by Suffix. Suffix indicates the
functional group present in the compound. It is placed after the root name.
Suffix = name of the functional group present in the compound.
- The root name also contains Prefix. Prefix is the groups attached to the root. It indicates the branched carbon atoms on the root chain and name according to the root specifying the carbon number on which it is placed. It contains –yl in name end. The prefix is placed before the root name.
Prefix = name of the branched carbon atoms on chain.
- The name of the alkane is given in the form
Prefix + Root + Suffix
(b)
Interpretation:
The name of the given compound has to be given.
Concept Introduction:
The hydrocarbons which contain only single bonds are said to be cycloalkanes. The general formula for alkanes can be given as
The cycloalkanes are named following some rules:
- The name of the alkane is given by the number of carbon atoms present in the ring. It is said to be Root of the alkane.
Root = number of carbon atoms in ring.
- To name the root, for one carbon atom, the root name use is meth-. For two carbon atoms, the root name is eth-, for three carbon atoms, it is prop-, for four carbon atoms, it is but-, for five carbon atoms, it is pent- and so on.
- The root name is followed by Suffix. Suffix indicates the functional group present in the compound. It is placed after the root name.
Suffix = name of the functional group present in the compound.
- The root name also contains Prefix. Prefix is the groups attached to the root. It indicates the branched carbon atoms on the root chain and name according to the root specifying the carbon number on which it is placed. It contains –yl in name end. The prefix is placed before the root name.
Prefix = name of the branched carbon atoms on chain.
- The name of the alkane is given in the form
Prefix + Root + Suffix
(c)
Interpretation:
The structure of the given compound (1,2-diethylcyclopentane) has to be drawn.
Concept Introduction:
The structure of the compound is given by its systematic name.
To give the structure from the name of the compound, the root name has to be identified. The root name indicates the number of carbon atoms present in the longest chain.
Then the functional group (suffix) has to be identified. It indicates whether any functional groups are present in the compound, it also gives whether the compound is an alkane or
The prefix of the name indicates the branched groups and their positions on the carbon chain.
The name of the compound is in the form
Prefix + Root + Suffix
(b)
Interpretation:
The structure of the given compound (2,4,5-trimethylnonane) has to be drawn.
Concept Introduction:
The structure of the compound is given by its systematic name.
To give the structure from the name of the compound, the root name has to be identified. The root name indicates the number of carbon atoms present in the longest chain.
Then the functional group (suffix) has to be identified. It indicates whether any functional groups are present in the compound, it also gives whether the compound is an alkane or alkene or alkyne.
The prefix of the name indicates the branched groups and their positions on the carbon chain.
The name of the compound is in the form
Prefix + Root + Suffix
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Chapter 15 Solutions
Chemistry: The Molecular Nature of Matter and Change
- Identify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forward
- CS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forwardCS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forwardThe following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forward
- Control Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forwardCollagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forwardיווי 10 20 30 40 50 60 70 3.5 3 2.5 2 1.5 1 [ppm] 3.5 3 2.5 2 1.5 1 6 [ppm] 1 1.5 -2.5 3.5arrow_forward
- 2H2S(g)+3O2(g)→2SO2(g)+2H2O(g) A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion. Question Which of the following predicts the theoretical yield of SO2(g) from the reaction? Responses 1.2 g Answer A: 1.2 grams A 41 g Answer B: 41 grams B 77 g Answer C: 77 grams C 154 g Answer D: 154 grams Darrow_forwardPart VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10arrow_forwardQ: Arrange BCC and Fec metals, in sequence from the Fable (Dr. R's slides) and Calculate Volume and Density. Aa BCC V 52 5 SFCCarrow_forward
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