The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated. Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond. In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

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Answer 1

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Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

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Answer 2

Question

Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

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Answer 4

Question

Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

Expert Solution & Answer

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Answer 5

Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

Answer 6

Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

Answer 7

Chapter 14.7, Problem 14.12P

Interpretation Introduction

Interpretation: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature is to be stated.

Concept introduction: In an elimination reaction, a substituent is removed from the compound and this removal of a substituent leads to the formation of a bond.

In a substitution reaction, one molecule or atom is replaced by the other molecule or atom from the compound

To determine: The mechanism for the formation of n- propyl ether and propene from n-propyl and the reason corresponding to the formation of propene is favoured at high temperature.

Answer 8

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Answer 9

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Answer 11

Ch. 14.2C - Rank the given solvents in decreasing order of...Ch. 14.2D - Prob. 14.2P Ch. 14.2D - In the presence of 18-crown-6, potassium...Ch. 14.3B - Give a common name (when possible) and a...Ch. 14.3C - Prob. 14.5P Ch. 14.3C - Name the following heterocyclic ethers.Ch. 14.4 - Propose a fragmentation to account for each...Ch. 14.5 - Prob. 14.8P Ch. 14.5 - Prob. 14.9P Ch. 14.6 - Prob. 14.10P

Solution Summary: The author explains that the mechanism for the formation of n-propyl ether and propene is favoured at high temperature.

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