
(a)
The molar analysis of the saturated air.
(a)

Answer to Problem 113RP
The molar analysis of water is
Explanation of Solution
Express the pressure of air.
Here, the saturation pressure at temperature of
Express the molar fraction of water.
Here, pressure of water is
Express the molar fraction of nitrogen.
Here, pressure of nitrogen is
Express the molar fraction of oxygen.
Here, pressure of oxygen is
Express the molar fraction of argon.
Here, pressure of oxygen is
Conclusion:
Refer Table A-4, “saturated water-temperature table”, and write the saturation pressure at temperature of
Perform unit conversion of atmospheric pressure from
Substitute
Substitute
Hence, the molar analysis of water is
Substitute
Hence, the molar analysis of nitrogen is
Substitute
Hence, the molar analysis of oxygen is
Substitute
Hence, the molar analysis of argon is
(b)
The density of air before and after the process.
(b)

Answer to Problem 113RP
The density of air before and after the process is
Explanation of Solution
Express the molar mass of dry air.
Here, total molar fraction is
Express the molar mass of saturated air.
Here, molar mass of water vapor is
Express the density of air before the process.
Here, gas constant of air is
Express the density of air after the process.
Here, gas constant of air is
Conclusion:
Refer Table A-1, “molar mass, gas constant, and the critical point properties”, and write the molar masses.
Refer Table A-1, “molar mass, gas constant, and the critical point properties”, and write the universal gas constant of air.
Substitute
Substitute
Perform the unit conversion of temperature from
Substitute
Hence, the density of air before the process is
Substitute
Hence, the density of air after the process is
From the result obtained in Equations (X) and (XI), It is obtained that the density of dry air is larger than that of saturated air as the molar mass of dry air being larger than that of water.
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Chapter 14 Solutions
Thermodynamics: An Engineering Approach
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