Explanation Given info: r ( s ) = r ( t o ) + R N + R ( ( sin ( k s ) ) T − ( cos k s ) N ) Concept used: If the order of function is n then the value after ` n differentiation will be zero. Calculation: r ( s ) = r ( t o ) + R N + R [ ( sin k s ) T − ( cos k s ) N ] Do single differentiation, r ' ( s ) = 0 + 0 + 1 k [ d d s ( sin k s ) T − d d s ( cos k s ) N ] = 1 K [ ( k cos k s ) T − ( − k sin k s ) N ] = T cos k s + N sin k s ...

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 14.4, Problem 81E

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Show that $r (s)$ and $r (s)$ agree to order $2$ at $s = 0.$

$r_{1} (s_{0}) = r_{2} (s_{0}), r_{1}' (s_{0}) = r_{2}' (s_{0}), r_{1} " (s_{0}) = r_{2} " (s_{0})$

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Chapter 14.4, Problem 80E

Chapter 14.4, Problem 82E

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Chapter 14 Solutions

CALCULUS (CLOTH)

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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Show that r ( s ) and r ( s ) agree to order 2 at s = 0. r 1 ( s 0 ) = r 2 ( s 0 ) , r 1 ' ( s 0 ) = r 2 ' ( s 0 ) , r 1 " ( s 0 ) = r 2 " ( s 0 )

Solution Summary: The author calculates that r ( s ) and the value after n differentiation will be zero.

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Show that $r (s)$ and $r (s)$ agree to order $2$ at $s = 0.$

$r_{1} (s_{0}) = r_{2} (s_{0}), r_{1}' (s_{0}) = r_{2}' (s_{0}), r_{1} " (s_{0}) = r_{2} " (s_{0})$

Want to see the full answer?

Chapter 14 Solutions

Show that r ( s ) and r ( s ) agree to order 2 at s = 0. r 1 ( s 0 ) = r 2 ( s 0 ) , r 1 ' ( s 0 ) = r 2 ' ( s 0 ) , r 1 " ( s 0 ) = r 2 " ( s 0 )

Solution Summary: The author calculates that r ( s ) and the value after n differentiation will be zero.

Videos

Show that r(s) and r(s) agree to order 2 at s=0. r1(s0)=r2(s0),r1'(s0)=r2'(s0),r1"(s0)=r2"(s0)

Want to see the full answer?

Chapter 14 Solutions

Show that $r (s)$ and $r (s)$ agree to order $2$ at $s = 0.$

$r_{1} (s_{0}) = r_{2} (s_{0}), r_{1}' (s_{0}) = r_{2}' (s_{0}), r_{1} " (s_{0}) = r_{2} " (s_{0})$