a. Explanation Given information: A quarterback throwsa football while standing at the very center of the field on the 50 yard line. The ball leaves his hand at a height of 5 ftsand has initial velocity v 0 = 40 i + 35 j + 32 k ft/s Assume an acceleration of 32 feet per square due to gravity and that the i vector points down the field toward the endzone and the j vector points to the sideline .The field is 150 feet in width and 300 feet in length . Formula Used: v ( t ) = ∫ a ( t ) d t r ( t ) = ∫ v ( t ) d t Calculation: ↑ v ( t ) = ∫ a ( t ) d t ↓ v ( t ) = ∫ − 32 k d t = − 32 t k + c 0 We know that initially t = 0 ; v ( 0 ) = v 0 = 40 i + 35 j + 32 k ft/s . v ( 0 ) = − 32 ( 0 ) k + c 0 c 0 = 40 i + 35 j + 32 k Therefore; v ( t ) = − 32 t k + 40 i + b. To determine To find: Whether the player in bound or out of bound when he receives the ball.

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 14.5, Problem 25E

To determine

To find: The position function that gives the position of the ball t seconds after its thrown.

To determine

To find: Whether the player in bound or out of bound when he receives the ball.

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Chapter 14.5, Problem 24E

Chapter 14.5, Problem 26E

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Chapter 14 Solutions

CALCULUS (CLOTH)

Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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The position function that gives the position of the ball t seconds after its thrown.

Solution Summary: The author calculates the position function of the ball t seconds after its thrown.

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To find: The position function that gives the position of the ball t seconds after its thrown.

To find: Whether the player in bound or out of bound when he receives the ball.

Want to see the full answer?

Chapter 14 Solutions