The compounds that have same degrees of unsaturation should be identified from the given set of compounds. Concept Introduction : IR spectral studies: It is a spectroscopic technique which is used to determine the functional groups present in the given compound sample by absorbing frequency in particular range with respect to the group present in the given sample. Wavenumber: It is defined as the number of waves in one centimeter. The wavenumber indicates the location of each signal with respect to the functional group in the molecule and its unit is cm -1 . The Hydrogen Deficiency Index (HDI): It is used to measure the number of degrees of unsaturation (double and triple bonds) present in a given molecule. It is determined by using the formula HDI = 1 2 [(2 × No . of Carbon atoms)+2+(No . of Nitrogen atoms) -(No . of Hydrogen atoms)-(No . of halogens)] To identify : The compounds that have same degrees of unsaturation.

Question

Want to see the full answer?

Answer 1

Question

Chapter 14.16, Problem 31PTS

Interpretation Introduction

Interpretation: The compounds that have same degrees of unsaturation should be identified from the given set of compounds.

Concept Introduction:

IR spectral studies: It is a spectroscopic technique which is used to determine the functional groups present in the given compound sample by absorbing frequency in particular range with respect to the group present in the given sample.

Wavenumber: It is defined as the number of waves in one centimeter. The wavenumber indicates the location of each signal with respect to the functional group in the molecule and its unit is cm-1 .

The Hydrogen Deficiency Index (HDI): It is used to measure the number of degrees of unsaturation (double and triple bonds) present in a given molecule. It is determined by using the formula

HDI = 12[(2×No. of Carbon atoms)+2+(No. of Nitrogen atoms) -(No. of Hydrogen atoms)-(No. of halogens)]

To identify: The compounds that have same degrees of unsaturation.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please help with number 6 I got a negative number could that be right?

1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.

Give the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.