Biology: The Unity and Diversity of Life (MindTap Course List)
14th Edition
ISBN: 9781305073951
Author: Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher: Cengage Learning
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Chapter 14, Problem 9SQ
Summary Introduction
Introduction: Tay-Sachs disease is caused due to the mutations in HEXA gene that encodes for lysozymal enzyme. It follows autosomal recessive inheritance, that is, two copies of mutated gene should be present for the occurrence of the disease.
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Students have asked these similar questions
What is Mendelian inheritance?
a. Mendelian genes code an entire phenotype so that children will not be clones of their parents.
b. Mendelian genetics are those genes that code for dominant or recessive illnesses but only if no polygenic traits cancel them out.
c. Mendelian genes sit at one loci with one allele from Mom and one allele from Dad.
d. Mendelian genetics is when two or more genes at two or more loci express one trait
If a genetic disease is inherited on the basis of an autosomal dominant gene, one would expect
to find which of the following?
A. Affected fathers have only affected children.
B. Affected mothers never have affected sons.
C. If both parents are affected, all of their offspring have the disease.
D. If a child has the disease, one of his or her grandparents also had the disease.
Two albino parents have four unaffected children. If albinism in the parents is given by mutations on two different genes (A and B) and complementation is observed in all four children, what are the genotypes of the parents?
A.
AaBb and AABB
B.
AABb and AaBB
C.
both parents are AaBb
D.
AAbb and BBaa
Chapter 14 Solutions
Biology: The Unity and Diversity of Life (MindTap Course List)
Ch. 14 - Constructing a pedigree is particularly useful...Ch. 14 - Prob. 2SQCh. 14 - Prob. 3SQCh. 14 - Prob. 4SQCh. 14 - Prob. 5SQCh. 14 - A trait that is present in a male child but not in...Ch. 14 - Color blindness is a case of ______ inheritance....Ch. 14 - A female child inherits one X chromosome from her...Ch. 14 - Prob. 1DAACh. 14 - Prob. 2DAA
Ch. 14 - Prob. 3DAACh. 14 - Prob. 9SQCh. 14 - Expression of the SRY gene on the Y chromosome...Ch. 14 - Prob. 11SQCh. 14 - Prob. 12SQCh. 14 - Prob. 13SQCh. 14 - Prob. 14SQCh. 14 - Match the chromosome terms appropriately. ____...Ch. 14 - Prob. 1GPCh. 14 - Does the phenotype indicated by the red circles...Ch. 14 - Human females have two X chromosomes (XX); males...Ch. 14 - A mutated allele responsible for Marfan syndrome...Ch. 14 - The somatic cells of most individuals with Down...Ch. 14 - Mutations in the genes for clotting factor VIII...
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- Duchenne muscular dystrophy is sex linked and usually affects only males. Victims of the disease become progressively weaker, starting early in life.a. What is the probability that a woman whose brother has Duchenne’s disease will have an affected child?b. If your mother’s brother (your uncle) had Duchenne’s disease, what is the probability that you have received the allele?c. If your father’s brother had the disease, what is the probability that you have received the allele?arrow_forwardAlkaptonuria is a metabolic disorder in which affected people produce black urine. Alkaptonuria results from an allele (a) that is recessive to the allele for normal metabolism (A). Sally has normal metabolism, but her brother has alkaptonuria. Sally’s father has alkaptonuria, and her mother has normal metabolism. a. Give the genotypes of Sally, her mother, her father, and her brother.b. If Sally’s parents have another child, what is the probability that this child will have alkaptonuria?c. If Sally marries a man with alkaptonuria, what is the probability thattheir first child will have alkaptonuria?arrow_forwardIn a trait that follows Mendelian rules of inheritance, what is the only way an organism can have the recessive phenotype? A. By having the homozygous recessive genotype B. By being heterozygous for that genotype C. It is not possible to get the recessive phenotype in Mendelian genetics D. If one parent is homozygous recessive for that trait, any offspring are guaranteed the recessive phenotype E. By being homozygous dominant for that genotypearrow_forward
- The condition phenylketonuria is caused by a recessive allele. There are two carriers who have progeny.a. Give the gene notation. b. Give the expected genotypic and phenotypic ratios. c. What is the probability that their child will be heterozygous if they have a normal child?d. What is the probability of having two affected children and one normal child if they have three children?arrow_forwardIn humans, hemophilia is an X-linked recessive condition characterized by the inability of blood to clot normally. A woman who is a carrier for hemophilia marries a man who has hemophilia. What are the genotypes of the woman and man, respectively? a. xH+xH+, xH+y b. xH+xH xH+y c. xH+xH xHy Od. XHXH, XH+y O e. xHxH xHyarrow_forwardWhich statement about the pattern of inheritance for a recessive X-linked allele is true? A. Unaffected parents can produce daughters who are affected. B. Unaffected parents can have sons who are affected and daughters who are carriers. C. Unaffected fathers can be carriers. D. Affected parents do not produce affected children. E. Every affected person has an affected parent.arrow_forward
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