a. a) Graph the function. b. b) Draw tangent lines to the graph at point whose x -coordinates are –2, 0, and 1. c. c) Find f ' ( x ) by determining lim x → 0 f ( x + h ) − f ( x ) h . d. d) Find f ' ( − 2 ) , f ' ( 0 , ) and f ' ( 1 ) . These slopes should match those of the lines you drew in part ( b ). f ( x ) = 1 2 x − 3
a. a) Graph the function. b. b) Draw tangent lines to the graph at point whose x -coordinates are –2, 0, and 1. c. c) Find f ' ( x ) by determining lim x → 0 f ( x + h ) − f ( x ) h . d. d) Find f ' ( − 2 ) , f ' ( 0 , ) and f ' ( 1 ) . These slopes should match those of the lines you drew in part ( b ). f ( x ) = 1 2 x − 3
Solution Summary: The author illustrates the graph of the function f(x)=12x-3.
a) Graph the function f(x) = 2x² - 9x + 10.
b) Draw a tangent line to the graph at the point whose x-coordinate is 3.
c) Find f'(x) by determining lim
f(x +h)- f(x)
R
d) Find f'(3). This slope should match that of the line you drew in part (b).
a) Choose the correct graph of the function.
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b) Choose the correct graph of the tangent line.
Click to select your answer(s).
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Find an equation for the tangent line to y = g(x) at the
point (2, g(2)). Write your result in point-slope form.
Submit
On the axes provided, sketch the tangent line to the
function g(x) at the point (2, g(2)).
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Got help on the last one but I don't know what the D'L rule is.
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Differential Equation | MIT 18.01SC Single Variable Calculus, Fall 2010; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=HaOHUfymsuk;License: Standard YouTube License, CC-BY