Explanation Explanation Given The concentration of NaOH is 0.100 M . The volume of NaOH is 25.0 mL . The concentration of HCl is 0.100 M The volume of HCl is 13.0 mL . The pH of the solution is 4.70 The pH of the solution is shown below. pH = − log [ H + ] Where, [ H + ] is the concentration of Hydrogen ions. Substitute the value of pH in the above equation to find the concentration of [ H + ] . pH = − log [ H + ] 4.7 = − log [ H + ] [ H + ] = 10 − 4.7 = 2 × 10 − 5 M Therefore, the number of moles of [ H + ] present per litre in final solution = 2 × 10 − 5 . The total volume of final solution = ( 25.0 + 13.0 ) mL =38 .0 mL The conversion of mL into L is done as, 1 mL = 0.001 L Hence, the conversion of 38.0 mL , 13.0 mL and 25.0 mL into L is done as, 38.0 mL = 38.0 × 0.001 L = 0 .038 L 25.0 mL = 25.0 × 0.001 L = 0 .025 L 13.0 mL = 13.0 × 0.001 L = 0 .013 L The concentration of any species is given as, Concentration = Number of moles Volume of solution in litres (1) Rearrange the above equation to obtain the value of number of moles. Number of moles = Concentration × Volume of solution in litres Substitute the value of concentration and volume of solution in above equation as, Number of moles = Concentration × Volume of solution in litres = 2.0 × 10 − 5 mole L × 0.038 L = 7 .6 × 10 − 7 moles Similarly, substitute the value of concentration and volume of NaOH in above equation as, Number of moles = Concentration × Volume of solution in litres = 0.100 mole L × 0.025 L = 0.0025 moles The reaction between acid HA and base NaOH is represented as, HA + NaOH → NaA + H 3 O + As it is seen from the equation that 1 mole of HA reacts with 1 mole of NaOH to produce 1 mole of NaA

Bundle: Chemistry: An Atoms First Approach, 2nd, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card

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ISBN: 9781305717633

Author: Steven S. Zumdahl, Susan A. Zumdahl

Publisher: Cengage Learning

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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Chapter 14, Problem 98AE

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Interpretation: The pH of solution of a weak acid HA with NaOH to which HCl is given. The relationship of pKa to the value of 4.70 is to be stated.

Concept introduction: A strong acid has a weak conjugate base while a weak acid has a strong conjugate base.

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Chapter 14, Problem 97AE

Chapter 14, Problem 99AE

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Chapter 14 Solutions

Bundle: Chemistry: An Atoms First Approach, 2nd, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card

Ch. 14 - What is meant by the presence of a common ion? How...Ch. 14 - Define a buffer solution. What makes up a buffer...Ch. 14 - Prob. 3RQ Ch. 14 - A good buffer generally contains relatively equal...Ch. 14 - Prob. 5RQ Ch. 14 - Prob. 6RQ Ch. 14 - Sketch the titration curve for a weak acid...Ch. 14 - Sketch the titration curve for a weak base...Ch. 14 - What is an acidbase indicator? Define the...Ch. 14 - Prob. 10RQ

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The pH of solution of a weak acid HA with NaOH to which HCl is given. The relationship of p K a to the value of 4.70 is to be stated. Concept introduction: A strong acid has a weak conjugate base while a weak acid has a strong conjugate base.

Solution Summary: The author explains the relationship between pH and 4.70 in the Henderson-Hasselbalch equation.

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Interpretation: The pH of solution of a weak acid HA with NaOH to which HCl is given. The relationship of pKa to the value of 4.70 is to be stated.

Concept introduction: A strong acid has a weak conjugate base while a weak acid has a strong conjugate base.

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Chapter 14 Solutions

The pH of solution of a weak acid HA with NaOH to which HCl is given. The relationship of p K a to the value of 4.70 is to be stated. Concept introduction: A strong acid has a weak conjugate base while a weak acid has a strong conjugate base.

Solution Summary: The author explains the relationship between pH and 4.70 in the Henderson-Hasselbalch equation.

Concept explainers

Videos

Interpretation: The pH of solution of a weak acid HA with NaOH to which HCl is given. The relationship of pKa to the value of 4.70 is to be stated. Concept introduction: A strong acid has a weak conjugate base while a weak acid has a strong conjugate base.

Want to see the full answer?

Chapter 14 Solutions

Interpretation: The pH of solution of a weak acid HA with NaOH to which HCl is given. The relationship of pKa to the value of 4.70 is to be stated.

Concept introduction: A strong acid has a weak conjugate base while a weak acid has a strong conjugate base.