Microelectronics: Circuit Analysis and Design
4th Edition
ISBN: 9780073380643
Author: Donald A. Neamen
Publisher: McGraw-Hill Companies, The
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Textbook Question
Chapter 14, Problem 8RQ
Define slew rate and define full−power bandwidth.
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can you please show working and steps. The answer is 8kohms.
PSD
A certain signal f(t) has the following PSD (assume 12 load):
| Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)]
(a) What is the mean power in the bandwidth w≤ 1 rad/sec?
(b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec?
(c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec?
(d) What is the total mean power in (t)?
Pav=
+
2T
SfLw) dw
- SALW)
An AM modulation waveform signal:-
p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt
(a) Sketch the amplitude spectrum of p(t).
(b) Find total power, sideband power and power efficiency.
(c) Find the average power containing of each sideband.
Chapter 14 Solutions
Microelectronics: Circuit Analysis and Design
Ch. 14 - Using the circuit and transistor parameters of...Ch. 14 - Prob. 14.2TYUCh. 14 - Prob. 14.1EPCh. 14 - Determine the closedloop input resistance at the...Ch. 14 - For a noninverting amplifier, the resistances are...Ch. 14 - An opamp with an openloop gain of AOL=105 is used...Ch. 14 - Prob. 14.3TYUCh. 14 - An operational amplifier connected in a...Ch. 14 - Prob. 14.5TYUCh. 14 - Prob. 14.6TYU
Ch. 14 - Find the closedloop input resistance of a voltage...Ch. 14 - An opamp with openloop parameters of AOL=2105 and...Ch. 14 - A 0.5 V input step function is applied at t=0 to a...Ch. 14 - The slew rate of the 741 opamp is 0.63V/s ....Ch. 14 - Prob. 14.8TYUCh. 14 - Prob. 14.8EPCh. 14 - Consider the active load bipolar duffamp stage in...Ch. 14 - Prob. 14.10EPCh. 14 - Prob. 14.11EPCh. 14 - Prob. 14.12EPCh. 14 - For the opamp circuit shown in Figure 14.28, the...Ch. 14 - Prob. 14.9TYUCh. 14 - List and describe five practical opamp parameters...Ch. 14 - What is atypical value of openloop, lowfrequency...Ch. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQCh. 14 - Prob. 6RQCh. 14 - Describe the gainbandwidth product property of a...Ch. 14 - Define slew rate and define fullpower bandwidth.Ch. 14 - Prob. 9RQCh. 14 - What is one cause of an offset voltage in the...Ch. 14 - Prob. 11RQCh. 14 - Prob. 12RQCh. 14 - Prob. 13RQCh. 14 - Prob. 14RQCh. 14 - Prob. 15RQCh. 14 - Prob. 16RQCh. 14 - Prob. 17RQCh. 14 - Prob. 14.1PCh. 14 - Consider the opamp described in Problem 14.1. In...Ch. 14 - Data in the following table were taken for several...Ch. 14 - Prob. 14.4PCh. 14 - Prob. 14.5PCh. 14 - Prob. 14.6PCh. 14 - Prob. 14.7PCh. 14 - Prob. 14.8PCh. 14 - An inverting amplifier is fabricated using 0.1...Ch. 14 - For the opamp used in the inverting amplifier...Ch. 14 - Prob. 14.11PCh. 14 - Consider the two inverting amplifiers in cascade...Ch. 14 - The noninverting amplifier in Figure P14.13 has an...Ch. 14 - For the opamp in the voltage follower circuit in...Ch. 14 - The summing amplifier in Figure P14.15 has an...Ch. 14 - Prob. 14.16PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Three inverting amplifiers, each with R2=150k and...Ch. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26PCh. 14 - Prob. 14.27PCh. 14 - Prob. D14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32PCh. 14 - Prob. 14.33PCh. 14 - Prob. 14.34PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - Prob. 14.37PCh. 14 - In the circuit in Figure P14.38, the offset...Ch. 14 - Prob. 14.39PCh. 14 - Prob. 14.40PCh. 14 - Prob. 14.41PCh. 14 - Prob. 14.42PCh. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.46PCh. 14 - Prob. D14.47PCh. 14 - Prob. 14.48PCh. 14 - Prob. 14.50PCh. 14 - Prob. 14.51PCh. 14 - Prob. D14.52PCh. 14 - Prob. D14.53PCh. 14 - Prob. 14.55PCh. 14 - Prob. 14.56PCh. 14 - Prob. 14.57PCh. 14 - The opamp in the difference amplifier...Ch. 14 - Prob. 14.61P
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- Can you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forward
- A. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forwardFind Io using Mesh analysisarrow_forwardFM station of 100 MHz carrier frequency modulated by a 20 kHz sinusoid with an amplitude of 10 volt, so that the peak frequency deviation is 25 kHz determine: 1) The BW of the FM signal. 2) The approximated BW if the modulating signal amplitude is increased to 50 volt. 3) The approximated BW if the modulating signal frequency is increased by 70%. 4) The amplitude of the modulating signal if the BW is 65 kHz.arrow_forward
- An FDM is used to multiplex two groups of signals using AM-SSB, the first group contains 25 speech signals, each has maximum frequency of 4 kHz, the second group contains 15 music signals, each has maximum frequency of 10 kHz. A guard bandwidth of 500 Hz is used bety each two signals and before the first one. 1. Find the BWmultiplexing 2. Find the BWtransmission if the multiplexing signal is modulated using AM-DSB-LC.arrow_forwardAn FM signal with 75 kHz deviation, has an input signal-to-noise ratio of 18 dB, with a modulating frequency of 15 kHz. 1) Find SNRO at demodulator o/p. 2) Find SNRO at demodulator o/p if AM is used with m=0.3. 3) Compare the performance in case 1) and 2).. Hint: for single tone AM-DSB-LC, SNR₁ = (2m²) (4)arrow_forwardFind Va and Vb using Nodal analysisarrow_forward
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