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Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Question
Chapter 14, Problem 8CQ
(a)
To determine
The increase in audibility of the tuning fork and its effect on time interval of vibration
(b)
To determine
The increase in audibility of the tuning fork and its effect on time interval of vibration
(c)
To determine
The increase in audibility of the tuning fork and its effect on time interval of vibration
(d)
To determine
The increase in audibility of the tuning fork and its effect on time interval of vibration
Expert Solution & Answer
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Please help me on the following question (Please refer to image below)An Olympic lifter (m = 103kg) is holding a lift with a mass of 350 kg. The barexerts a purely vertical force that is equally distributed between both hands. Each arm has amass of 9 kg, are 0.8m long and form a 40° angle with the horizontal. The CoM for each armis 0.5 m from hand. Assuming the lifter is facing us in the diagram below, his right deltoidinserts 14cm from the shoulder at an angle of 13° counter-clockwise from the humerus.A) You are interested in calculating the force in the right deltoid. Draw a free body diagramof the right arm including the external forces, joint reaction forces, a coordinate system andstate your assumptions.B) Find the force exerted by the right deltoidC) Find the shoulder joint contact force. Report your answer using the magnitude and directionof the shoulder force vector.
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Question 6:
Chlorine is widely used to purify municipal water supplies and to treat swimming pool
waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr
and 24°C.
(a) How many grams of Cl₂ are in the sample?
⚫ Atomic mass of CI = 35.453 g/mol
• Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol
Solution:
Use the Ideal Gas Law:
Step 1: Convert Given Values
• Pressure: P = 895 torr → atm
PV=
= nRT
1
P = 895 ×
= 1.1789 atm
760
•
Temperature: Convert to Kelvin:
T24273.15 = 297.15 K
• Gas constant: R = 0.0821 L atm/mol. K
Volume: V = 8.70 L
Step 2: Solve for n
.
PV
n =
RT
n =
(1.1789)(8.70)
(0.0821)(297.15)
10.25
n =
= 0.420 mol
24.405
Step 3: Calculate Mass of Cl₂
Final Answer: 29.78 g of Cl₂.
mass nx M
mass=
(0.420)(70.906)
mass=
29.78 g
Chapter 14 Solutions
Principles of Physics: A Calculus-Based Text
Ch. 14.1 - Prob. 14.1QQCh. 14.2 - Prob. 14.2QQCh. 14.3 - When a standing wave is set up on a string fixed...Ch. 14.4 - Prob. 14.4QQCh. 14.4 - Prob. 14.5QQCh. 14.5 - You are tuning a guitar by comparing the sound of...Ch. 14 - A flute has a length of 58.0 cm. If the speed of...Ch. 14 - Prob. 2OQCh. 14 - In Figure OQ14.3, a sound wave of wavelength 0.8 m...Ch. 14 - Prob. 4OQ
Ch. 14 - Prob. 5OQCh. 14 - Prob. 6OQCh. 14 - Prob. 7OQCh. 14 - Prob. 8OQCh. 14 - Prob. 9OQCh. 14 - Prob. 10OQCh. 14 - A standing wave having three nodes is set up in a...Ch. 14 - Prob. 1CQCh. 14 - Prob. 2CQCh. 14 - Prob. 3CQCh. 14 - Prob. 4CQCh. 14 - What limits the amplitude of motion of a real...Ch. 14 - Prob. 6CQCh. 14 - Prob. 7CQCh. 14 - Prob. 8CQCh. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Prob. 8PCh. 14 - Prob. 9PCh. 14 - Prob. 10PCh. 14 - Prob. 11PCh. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - A string with a mass m = 8.00 g and a length L =...Ch. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Review. A sphere of mass M is supported by a...Ch. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - The overall length of a piccolo is 32.0 cm. The...Ch. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Two adjacent natural frequencies of an organ pipe...Ch. 14 - Do not stick anything into your ear! Estimate the...Ch. 14 - Prob. 37PCh. 14 - As shown in Figure P14.37, water is pumped into a...Ch. 14 - Prob. 39PCh. 14 - Prob. 40PCh. 14 - Prob. 41PCh. 14 - Why is the following situation impossible? A...Ch. 14 - 23. An air column in a glass tube is open at one...Ch. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Prob. 46PCh. 14 - Prob. 47PCh. 14 - Prob. 48PCh. 14 - Some studies suggest that the upper frequency...Ch. 14 - Prob. 50PCh. 14 - An earthquake can produce a seiche in a lake in...Ch. 14 - Prob. 52PCh. 14 - Prob. 53PCh. 14 - Prob. 54PCh. 14 - Prob. 55PCh. 14 - A nylon string has mass 5.50 g and length L = 86.0...Ch. 14 - Prob. 57PCh. 14 - Prob. 58PCh. 14 - Prob. 59PCh. 14 - Review. For the arrangement shown in Figure...Ch. 14 - Prob. 61PCh. 14 - Prob. 62PCh. 14 - Prob. 63PCh. 14 - Prob. 64PCh. 14 - Prob. 65PCh. 14 - Prob. 66PCh. 14 - Prob. 67PCh. 14 - Review. Consider the apparatus shown in Figure...Ch. 14 - Prob. 69P
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