Chapter 14, Problem 88AE

(a)

Interpretation Introduction

Interpretation:

Volume of water added to concentrated ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ to prepare $8.4\text{ L}$ of $1.5M{\text{ H}}_2{\text{SO}}_4$ has to be determined.

Concept Introduction:

Expression for molarity equation is as follows:

  $M_1{V}_1=M_2{V}_2$        (1)

Here,

$M_1$ is molarity of concentrate solution.

$V_1$ is volume of concentrate solution.

$M_2$ is molarity of diluted solution.

$V_2$ is volume of diluted solution.

(b)

Interpretation Introduction

Interpretation:

Volume of water added to concentrated ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ to prepare $8.4\text{ L}$ of $1.5M{\text{ H}}_2{\text{SO}}_4$ has to be determined.

Concept Introduction:

Molarity is amount of solute per $1\text{ L}$ of solution. Expression to calculate molarity is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$

(c)

Interpretation Introduction

Interpretation:

Moles present in each milliliter of diluted solution have to be determined.

Concept Introduction:

Refer to part (b).