Chapter 14, Problem 62AE

Interpretation Introduction

Interpretation:

Grams of $10.0\text{ \% NaOH}$ solution by mass required to neutralize $250.0\text{ g}$ of $1.0m$ solution of $\text{HCl}$ has to be determined.

Concept Introduction:

Molality is amount of solute present in one kilogram of solvent. Expression for molality of solution is as follows:

  $\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass }\left(\text{kg}\right)\text{of solvent}}$