Chapter 14, Problem 66AE

Interpretation Introduction

Interpretation:

Grams of ${\text{KNO}}_{\text{3}}$ required to make $450\text{ mL}$ of solution that contains $5.5\text{ mg/mL}$ of potassium ion have to be determined. Also, molarity of solution has to be determined.

Concept Introduction:

Molarity is amount of solute present in $1\text{ L}$ of solution. Formula to calculate molarity of solution is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$