Explanation: Given The wave function for the electron in one dimensional system is, Ψ ( x ) = sin x The probability density curve for the function Ψ 2 ( x ) = sin 2 x contains all the positive values of the given function over the whole range. Therefore, the probability density curve for the given function is, Figure 1 (b) Explanation: Given The wave function for the electron in one dimensional system is, Ψ ( x ) = sin x The probability of finding electron for the given function is maximum on the values of x where the probability density curve has the maximum value. For the given function the value of sin x is maximum at the values x = π 2 and x = 3 π 2 . Therefore, the probability density curve for the given function has a peak at these values of x where probability of finding an electron is maximum. (c) Explanation: The wave function for the electron in one dimensional system is, Ψ ( x ) = sin x The probability of finding electron for the given function is minimum on the values of x where the probability density curve has the minimum value. For the given function the value of sin x is zero at the value of x = π . Therefore, the probability density curve for the given function has a node at this value of x where probability of finding electron is nil. Conclusion: (a) The probability density curve for the given function is as follows: (b) The values of x is maximum at x = π 2 and x = 3 π 2 . (c) The probability of finding an electron at x = π is zero and this point is called node.
Explanation: Given The wave function for the electron in one dimensional system is, Ψ ( x ) = sin x The probability density curve for the function Ψ 2 ( x ) = sin 2 x contains all the positive values of the given function over the whole range. Therefore, the probability density curve for the given function is, Figure 1 (b) Explanation: Given The wave function for the electron in one dimensional system is, Ψ ( x ) = sin x The probability of finding electron for the given function is maximum on the values of x where the probability density curve has the maximum value. For the given function the value of sin x is maximum at the values x = π 2 and x = 3 π 2 . Therefore, the probability density curve for the given function has a peak at these values of x where probability of finding an electron is maximum. (c) Explanation: The wave function for the electron in one dimensional system is, Ψ ( x ) = sin x The probability of finding electron for the given function is minimum on the values of x where the probability density curve has the minimum value. For the given function the value of sin x is zero at the value of x = π . Therefore, the probability density curve for the given function has a node at this value of x where probability of finding electron is nil. Conclusion: (a) The probability density curve for the given function is as follows: (b) The values of x is maximum at x = π 2 and x = 3 π 2 . (c) The probability of finding an electron at x = π is zero and this point is called node.
Given The wave function for the electron in one dimensional system is,
Ψ(x)=sinx
The probability density curve for the function Ψ2(x)=sin2x contains all the positive values of the given function over the whole range. Therefore, the probability density curve for the given function is,
Figure 1
(b)
Explanation:
Given The wave function for the electron in one dimensional system is,
Ψ(x)=sinx
The probability of finding electron for the given function is maximum on the values of x where the probability density curve has the maximum value. For the given function the value of sinx is maximum at the values x=π2 and x=3π2 . Therefore, the probability density curve for the given function has a peak at these values of x where probability of finding an electron is maximum.
(c)
Explanation: The wave function for the electron in one dimensional system is,
Ψ(x)=sinx
The probability of finding electron for the given function is minimum on the values of x where the probability density curve has the minimum value. For the given function the value of sinx is zero at the value of x=π . Therefore, the probability density curve for the given function has a node at this value of x where probability of finding electron is nil.
Conclusion:
(a) The probability density curve for the given function is as follows:
(b) The values of x is maximum at x=π2 and x=3π2 . (c) The probability of finding an electron at x=π is zero and this point is called node.
Hi!!
Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required.
Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!
Hi!!
Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required.
Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!
. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
2°C. +2°C. < cleavage
Bond A
• CH3 + 26. t cleavage
2°C• +3°C•
Bond C
Cleavage
CH3 ZC
'2°C. 26.
E
Strongest
3°C. 2C.
Gund
Largest
BDE
weakest bond
In that molecule
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
Weakest
C bond
Produces
A
Weakest
Bond
Most
Strongest
Bond
Stable radical
Strongest Gund
produces least stable
radicals
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
人
8°C. formed in
bound C
cleavage
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
methyl radical
•CH3
formed in
bund A Cleavage
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