Concept explainers
(a)
Interpretation:
Compounds from the
Concept introduction:
The
The splitting of signals predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound. The single signal is split into multiple peaks called the multiplicity of the signal. Splitting of signals is done according to the
According to the
(b)
Interpretation:
Compounds from the
Concept introduction:
The
The splitting of signals predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound. The single signal is split into multiple peaks called the multiplicity of the signal. Splitting of signals is done according to the
According to the
(c)
Interpretation:
Compounds from the
Concept introduction:
The
The splitting of signals predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound. The single signal is split into multiple peaks called the multiplicity of the signal. Splitting of signals is done according to the
According to the
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EBK ORGANIC CHEMISTRY
- Following are 1H-NMR spectra for compounds G, H, and I, each with the molecular formula C5H12O. Each is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas. (a) Propose structural formulas of compounds G, H, and I. (b) Explain why there are four lines between 0.86 and 0.90 for compound G. (c) Explain why the 2H multiplets at 1.5 and 3.5 for compound H are so complex.arrow_forwardAscaridole is a natural product that has been used to treat intestinal worms. Explain why the two methyls on the isopropyl group in ascaridole appear in its 1H-NMR spectrum as four lines of equal intensity, with two sets of two each separated by 7 Hz.arrow_forwardAn unknown compound has the formula C10H12O. Elucidate its structure by scrutinizing its 1H NMR spectra, shown. Specifically, label each different type of H atom in the final structure with its NMR chemical shift in ppm.arrow_forward
- Select the compound from each group that matches the HNMR spectrum shown below.arrow_forwardIdentify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound A exhibits peaks at 1.75 (doublet, 3 H, J = 6.9 Hz) and 5.89 (quartet, 1 H, J = 6.9 Hz) ppm. Compound B exhibits peaks at 4.16 (singlet, 2 H), 5.42 (doublet, 1 H, J = 1.9 Hz), and 5.59 (doublet, 1 H, J = 1.9 Hz) ppm.arrow_forwardWhat is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?arrow_forward
- Identify each compound below from its molecular formula and its 13C NMR spectrum.arrow_forwardCompound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forwardThe following 1H NMR spectra are for four compounds, each with molecular formula of C6H12O2. Identify the compoundsarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning