Chapter 14, Problem 52PE

Interpretation Introduction

Interpretation:

Molarity of ${\text{HgCl}}_2$ in stock solution prepared by dissolution of $74.15\text{ g}$ of ${\text{HgCl}}_2$ to total volume of $250.0\text{ mL}$ has to be determined.

Concept Introduction:

Molarity is amount of solute present in $1\text{ L}$ of solution. Formula to calculate molarity of solution is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$