Chapter 14, Problem 30PE

(a)

Interpretation Introduction

Interpretation:

Volume of concentrated $\text{18 }M{\text{ H}}_{\text{2}}{\text{SO}}_{\text{4}}$ required to prepare $225\text{ mL}$ of $\text{2}\text{.0 }M{\text{ H}}_{\text{2}}{\text{SO}}_{\text{4}}$ has to be determined.

Concept Introduction:

Molarity is amount of solute present in $1\text{ L}$ of solution. Expression for molarity equation is as follows:

  $M_1{V}_1=M_2{V}_2$        (1)

Here,

$M_1$ is molarity of dilute solution.

$V_1$ is volume of dilute solution.

$M_2$ is molarity of concentrated solution.

$V_2$ is volume of concentrated solution.

(b)

Interpretation Introduction

Interpretation:

Volume of concentrated $\text{15 }M{\text{ NH}}_3$ required to prepare $\text{75 mL}$ of $\text{1}\text{.0 }M{\text{ NH}}_3$ has to be determined.

Concept Introduction:

Refer to part (a).