![FOUND.OF COLLEGE CHEMISTRY](https://www.bartleby.com/isbn_cover_images/9781119234555/9781119234555_largeCoverImage.gif)
FOUND.OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119234555
Author: Hein
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 14, Problem 33RQ
Interpretation Introduction
Interpretation:
Freezing point of mixture of water and ice is
Concept Introduction:
Colligative properties are dependent on amount of solute particles and not on their natures. These are caused due to addition of nonvolatile solute in any solution. Below mentioned are colligative properties.
1. Freezing point depression
2. Boiling point elevation
3. Vapor pressure lowering
4. Osmotic pressure
Expert Solution & Answer
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Students have asked these similar questions
When 8.6 grams of a certain compound is dissolved in 78 grams of water in a calorimeter, the temperature of the calorimeter changes from 25.00ºC to 23.09 ºC. Assuming that the specific heat capacity for the resulting solution is 4.184 J/(g oC), and the heat for this solvation is found as x kJ, what is the value of x?
A constant pressure calorimeter contains 286 g of water at 20.0 °C. A 13.41 g of substance X (molar mass 154 g/mol) at 20.0°C was dissolved in this water. The temperature of the solution increased to 23.5 °C. Assuming the specific heat of the mixture is 4.184 J g‑1°C‑1, and the density of the solution is 1.00 g/cm3, calculate the enthalpy change (in kJ) for the dissolution of 1 mole of X.
What is the enthalpy change when 8.20 moles ammonium chloride form in the following equation?
N2 (g) + 4 H2 (g) + Cl2 (g) --> 2 NH4Cl (s)
Delta H = – 628.8 kJ
a. – 2.58 x 103 kJ
b. – 1.29 x 103 kJ
c. + 314.4 kJ
d. – 314.4 kJ
e. – 628.8 kJ
f. – 5.16 x 103 kJ
g. none of these
d. – 314.4 kJ
Chapter 14 Solutions
FOUND.OF COLLEGE CHEMISTRY
Ch. 14.1 - Prob. 14.1PCh. 14.2 - Prob. 14.2PCh. 14.3 - Prob. 14.3PCh. 14.4 - Prob. 14.4PCh. 14.4 - Prob. 14.5PCh. 14.4 - Prob. 14.6PCh. 14.4 - Prob. 14.7PCh. 14.4 - Prob. 14.8PCh. 14.4 - Prob. 14.9PCh. 14.4 - Prob. 14.10P
Ch. 14.5 - Prob. 14.11PCh. 14.5 - Prob. 14.12PCh. 14 - Prob. 1RQCh. 14 - Prob. 2RQCh. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQCh. 14 - Prob. 6RQCh. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - Prob. 9RQCh. 14 - Prob. 10RQCh. 14 - Prob. 11RQCh. 14 - Prob. 12RQCh. 14 - Prob. 13RQCh. 14 - Prob. 14RQCh. 14 - Prob. 15RQCh. 14 - Prob. 16RQCh. 14 - Prob. 17RQCh. 14 - Prob. 18RQCh. 14 - Prob. 19RQCh. 14 - Prob. 20RQCh. 14 - Prob. 21RQCh. 14 - Prob. 22RQCh. 14 - Prob. 23RQCh. 14 - Prob. 24RQCh. 14 - Prob. 25RQCh. 14 - Prob. 26RQCh. 14 - Prob. 27RQCh. 14 - Prob. 28RQCh. 14 - Prob. 29RQCh. 14 - Prob. 30RQCh. 14 - Prob. 31RQCh. 14 - Prob. 32RQCh. 14 - Prob. 33RQCh. 14 - Prob. 34RQCh. 14 - Prob. 35RQCh. 14 - Prob. 37RQCh. 14 - Prob. 38RQCh. 14 - Prob. 39RQCh. 14 - Prob. 40RQCh. 14 - Prob. 41RQCh. 14 - Prob. 42RQCh. 14 - Prob. 1PECh. 14 - Prob. 2PECh. 14 - Prob. 3PECh. 14 - Prob. 4PECh. 14 - Prob. 5PECh. 14 - Prob. 6PECh. 14 - Prob. 7PECh. 14 - Prob. 8PECh. 14 - Prob. 9PECh. 14 - Prob. 10PECh. 14 - Prob. 11PECh. 14 - Prob. 12PECh. 14 - Prob. 13PECh. 14 - Prob. 14PECh. 14 - Prob. 15PECh. 14 - Prob. 16PECh. 14 - Prob. 17PECh. 14 - Prob. 18PECh. 14 - Prob. 19PECh. 14 - Prob. 20PECh. 14 - Prob. 21PECh. 14 - Prob. 22PECh. 14 - Prob. 23PECh. 14 - Prob. 24PECh. 14 - Prob. 25PECh. 14 - Prob. 26PECh. 14 - Prob. 27PECh. 14 - Prob. 28PECh. 14 - Prob. 29PECh. 14 - Prob. 30PECh. 14 - Prob. 31PECh. 14 - Prob. 32PECh. 14 - Prob. 33PECh. 14 - Prob. 34PECh. 14 - Prob. 35PECh. 14 - Prob. 36PECh. 14 - Prob. 37PECh. 14 - Prob. 38PECh. 14 - Prob. 39PECh. 14 - Prob. 40PECh. 14 - Prob. 41PECh. 14 - Prob. 42PECh. 14 - Prob. 44PECh. 14 - Prob. 45PECh. 14 - Prob. 46PECh. 14 - Prob. 47PECh. 14 - Prob. 48PECh. 14 - Prob. 49PECh. 14 - Prob. 50PECh. 14 - Prob. 51PECh. 14 - Prob. 52PECh. 14 - Prob. 53AECh. 14 - Prob. 54AECh. 14 - Prob. 55AECh. 14 - Prob. 56AECh. 14 - Prob. 57AECh. 14 - Prob. 58AECh. 14 - Prob. 59AECh. 14 - Prob. 60AECh. 14 - Prob. 61AECh. 14 - Prob. 62AECh. 14 - Prob. 63AECh. 14 - Prob. 65AECh. 14 - Prob. 66AECh. 14 - Prob. 67AECh. 14 - Prob. 68AECh. 14 - Prob. 69AECh. 14 - Prob. 70AECh. 14 - Prob. 71AECh. 14 - Prob. 72AECh. 14 - Prob. 73AECh. 14 - Prob. 74AECh. 14 - Prob. 75AECh. 14 - Prob. 76AECh. 14 - Prob. 77AECh. 14 - Prob. 78AECh. 14 - Prob. 79AECh. 14 - Prob. 80AECh. 14 - Prob. 81AECh. 14 - Prob. 82AECh. 14 - Prob. 83AECh. 14 - Prob. 84AECh. 14 - Prob. 85AECh. 14 - Prob. 86AECh. 14 - Prob. 87AECh. 14 - Prob. 88AECh. 14 - Prob. 90AECh. 14 - Prob. 91AECh. 14 - Prob. 92AECh. 14 - Prob. 93AECh. 14 - Prob. 94AECh. 14 - Prob. 95AECh. 14 - Prob. 96AECh. 14 - Prob. 97AECh. 14 - Prob. 98AECh. 14 - Prob. 99CECh. 14 - Prob. 100CECh. 14 - Prob. 102CECh. 14 - Prob. 103CECh. 14 - Prob. 104CECh. 14 - Prob. 105CE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- 3. Which one of the following compounds would you expect to have the highest heat of solution? CaSO4·2 H2O, CaSO4, or CaSO4·10 H2O?arrow_forward3.66 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70 °C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・ °C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.arrow_forwardThe salt cesium bromide is soluble in water. When 8.46 g of CsBr is dissolved in 117.00 g of water, the temperature of the solution decreases from 25.00 to 22.79 °C. Based on this observation, calculate the enthalpy of dissolution of CsBr (in kJ/mol).Assume that the specific heat of the solution is 4.184 J/g °C and that the heat absorbed by the calorimeter is negligible. Change in H dissolution: _____kJ/molarrow_forward
- 192,690 J of heat is requred to raise the temperature of 5.0 moles of liquid methanol, CH3OH, from 25.0 °C to its boiling point (64.6 °C) and then to completely evaporate the methanol at that temperature. The specific heat of liquid methanol is 2.53 J g─1 K─1. Calculate the enthalpy ofvaporisation of the compound.arrow_forwardWhen 84.64 grams of fictional compound X is added to water to make 449.6 grams of solution, the temperature increases from 20.93 °C to 52.89 °C. What is the heat of solution for compound X given that the molar mass of compound X is 78.43 g/mol? Assume the specific heat capacity of the solution is 4.18 J/g°C. -60.07 kJ/mol 55.66 kJ/mol -55.66 kJ/mol 18.33 kJ/mol 60.07 kJ/molarrow_forwardUse the Born Haber cycle to calculate the lattice energy of Na2O(s) from the following data. Ionization energy of Na(g ) = 485 kJ mol-1 Electron Affinity of O(g) for two electrons = 553 kJ mol-1 Energy to Sublime Na(s) = 109 kJ mol-1 Bond energy of O2 = 449 kJ mol-1 ArxnH for 2 Na(s) + 1/2 O2(g) -> Na2O(s) = -466 kJ mol-1arrow_forward
- ) The salt potassium perchlorate is soluble in water. When 2.84 g of KClO4 is dissolved in 106.00 g of water, the temperature of the solution decreases from 25.00 to 22.54 °C. Based on this observation, calculate the enthalpy of dissolution of KClO4 (in kJ/mol).Assume that the specific heat of the solution is 4.184 J/g °C and that the heat absorbed by the calorimeter is negligible.arrow_forward3. Maximum solubility of an ionic compounds in water depend on different sets of conditions. Out of five sets of conditions (given below), which one is the best for getting maximum solubility? A. The magnitude of the lattice energy should be large, and the enthalpy of hydration of the ions should be large. B. The enthalpy of hydration (Delta H) of the cation should be equal to the enthalpy of hydration of the anion, regardless of the magnitude of the lattice energy C. The magnitude of the lattice energy should be small, and the enthalpy of hydration of the ions should be small. D. The magnitude of the lattice energy should be small, and the enthalpy of hydration of the ions should be large. E. The magnitude of the lattice energy should be large, and the enthalpy of hydration of the ions should be small.arrow_forward2.503 g of ammonium chloride NH4CI are added to a calorimeter cup containing 25.30 g of water at 22.0°C. The temperature of the calorimeter decreases to 17.3°C. Assume the specific heat of solution is 4.184 J/g°C. Assume the calorimeter constant you determined in question 1 Determine the molar enthalpy of dissolution of NH4CI in kJ/mol.arrow_forward
- A 22.00g sample of XCl4 is dissolved completely in 60.0 g of water(Kb = 0.512°C/m). The solution boils at 103.81°C. Determine the identity of Xarrow_forwardIf one mixes 50 cm3 of EtOH and 50 cm3 of H2O at room temperature; will the total volume of the solution will be 100.0 cm3? Justify your answer with appropriate calculations and explanations.arrow_forwardWhen 54.29 grams of fictional compound X is added to water to make 341.3 grams of solution, the temperature increases from 20.29 °C to 83.39 °C. What is the heat of solution for compound X given that the molar mass of compound X is 154.77 g/mol? Assume the specific heat capacity of the solution is 4.18 J/g°C. a -256.6 kJ/mol b 15.50 kJ/mol c 256.6 kJ/mol d -90.02 kJ/mol e 90.02 kJ/molarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9780534420123/9780534420123_smallCoverImage.gif)
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079243/9781305079243_smallCoverImage.gif)
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337398909/9781337398909_smallCoverImage.gif)
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399425/9781337399425_smallCoverImage.gif)
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781559539418/9781559539418_smallCoverImage.gif)
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199047/9781285199047_smallCoverImage.gif)
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY