Program Explanation Given information: The total population of the city is 100000 and after one week 10000 people had heard the rumor. The increasing rate of the number of the persons who heard the rumor is directly proportional to the number of people who have not heard it. Calculation: Consider N is the number of people who heard the rumor and P is the total population. Therefore, the number of people who have not heard the rumor. It is given that the increasing rate of the number of the persons who heard the rumor is directly proportional to the number of people who have not heard it. Therefore, it can be mathematically expressed as, d N d t = k ( 100 , 000 − N ) Now use the method of separation of the variable to solve the above differential equation. d N d t = k ( 100 , 000 − N ) d N ( 100 , 000 − N ) = k d t Now integrate both sides. ∫ d N ( 100000 − N ) = ∫ k d T − ln ( 100 , 000 − N ) = k t + c 1 100 , 000 − N = e k t + c 1 100 , 000 − N = d e k t Therefore, the number of the person who heard the rumor function is as follows, N = 100000 − D − 1 e − k t ........ (1) The given initial condition of number of the person who heard the rumor is N ( 0 ) = 0 . Now apply the initial condition N ( 0 ) = 0 on equation (1) to obtain the value of c . N = 100000 − D − 1 e − k t 0 = 100000 − D − 1 e − k ( 0 ) D − 1 = 100000 It is given that after 7 days the number of the person who heard the rumor is 10000 as N ( 7 ) = 10000

Differential Equations: Computing and Modeling (5th Edition), Edwards, Penney & Calvis

5th Edition

ISBN: 9780321816252

Author: C. Henry Edwards, David E. Penney, David Calvis

Publisher: PEARSON

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A naïve solution for the above-stated problem is to evaluate all of the possible combinations of different pieces of varying size to find the maximum revenue-generating combination. Although this method seems the easiest and quick to practice, it has exp…

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Chapter 1.4, Problem 47P

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Program Description: Purpose of the problem is to find the time when half of the population heard the rumor.

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Chapter 1.4, Problem 46P

Chapter 1.4, Problem 48P

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Taylor Series Approximation Example- H.W More terms used implies better approximation f(x) 4 f(x) Zero order f(x + 1) = f(x;) First order f(x; + 1) = f(x;) + f'(x;)h 1.0 Second order 0.5 True f(x + 1) = f(x) + f'(x)h + ƒ"(x;) h2 2! f(x+1) 0 x; = 0 x+1 = 1 x h f(x)=0.1x4-0.15x³- 0.5x2 -0.25x + 1.2 51 Taylor Series Approximation H.w: Smaller step size implies smaller error Errors f(x) + f(x,) Zero order f(x,+ 1) = f(x) First order 1.0 0.5 Reduced step size Second order True f(x + 1) = f(x) + f'(x)h f(x; + 1) = f(x) + f'(x)h + "(xi) h2 f(x,+1) O x₁ = 0 x+1=1 Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5 iterations (or & s= 5%) for f(x)=0.1x 0.15x³-0.5x²- 0.25x + 1.2 52

Could you explain this using the formula I attached and polar coorindates

Could you explain this using the formula I attached and polar coordinates

Chapter 1 Solutions

Differential Equations: Computing and Modeling (5th Edition), Edwards, Penney & Calvis

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Ch. 1.1 - Prob. 11P Ch. 1.1 - Prob. 12P Ch. 1.1 - Prob. 13P Ch. 1.1 - Prob. 14P Ch. 1.1 - Prob. 15P Ch. 1.1 - Prob. 16P Ch. 1.1 - Prob. 17P Ch. 1.1 - Prob. 18P Ch. 1.1 - Prob. 19P Ch. 1.1 - Prob. 20P Ch. 1.1 - Prob. 21P Ch. 1.1 - Prob. 22P Ch. 1.1 - Prob. 23P Ch. 1.1 - Prob. 24P Ch. 1.1 - Prob. 25P Ch. 1.1 - Prob. 26P Ch. 1.1 - Prob. 27P Ch. 1.1 - Prob. 28P Ch. 1.1 - Prob. 29P Ch. 1.1 - Prob. 30P Ch. 1.1 - Prob. 31P Ch. 1.1 - Prob. 32P Ch. 1.1 - Prob. 33P Ch. 1.1 - Prob. 34P Ch. 1.1 - Prob. 35P Ch. 1.1 - Prob. 36P Ch. 1.1 - Prob. 37P Ch. 1.1 - Prob. 38P Ch. 1.1 - Prob. 39P Ch. 1.1 - Prob. 40P Ch. 1.1 - Prob. 41P Ch. 1.1 - Prob. 42P Ch. 1.1 - Prob. 43P Ch. 1.1 - Prob. 44P Ch. 1.1 - Prob. 45P Ch. 1.1 - Prob. 46P Ch. 1.1 - Prob. 47P Ch. 1.1 - Prob. 48P Ch. 1.2 - Prob. 1P Ch. 1.2 - Prob. 2P Ch. 1.2 - Prob. 3P Ch. 1.2 - Prob. 4P Ch. 1.2 - In Problems 1 through 10, find a function y=f(x)...Ch. 1.2 - Prob. 6P Ch. 1.2 - Prob. 7P Ch. 1.2 - Prob. 8P Ch. 1.2 - Prob. 9P Ch. 1.2 - Prob. 10P Ch. 1.2 - 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Prob. 62P Ch. 1.4 - Prob. 63P Ch. 1.4 - (The clepsydra, or water clock) A 12 h water clock...Ch. 1.4 - Prob. 65P Ch. 1.4 - Prob. 66P Ch. 1.4 - Prob. 67P Ch. 1.4 - Figure 1.4.11 shows a bead sliding down a...Ch. 1.4 - Prob. 69P Ch. 1.5 - Prob. 1P Ch. 1.5 - Prob. 2P Ch. 1.5 - Prob. 3P Ch. 1.5 - Prob. 4P Ch. 1.5 - Prob. 5P Ch. 1.5 - Prob. 6P Ch. 1.5 - Prob. 7P Ch. 1.5 - Prob. 8P Ch. 1.5 - Prob. 9P Ch. 1.5 - Prob. 10P Ch. 1.5 - Prob. 11P Ch. 1.5 - Prob. 12P Ch. 1.5 - Prob. 13P Ch. 1.5 - Prob. 14P Ch. 1.5 - Prob. 15P Ch. 1.5 - Prob. 16P Ch. 1.5 - Prob. 17P Ch. 1.5 - Prob. 18P Ch. 1.5 - Prob. 19P Ch. 1.5 - Prob. 20P Ch. 1.5 - Prob. 21P Ch. 1.5 - Prob. 22P Ch. 1.5 - Prob. 23P Ch. 1.5 - Prob. 24P Ch. 1.5 - Prob. 25P Ch. 1.5 - Prob. 26P Ch. 1.5 - Prob. 27P Ch. 1.5 - Prob. 28P Ch. 1.5 - Prob. 29P Ch. 1.5 - Prob. 30P Ch. 1.5 - Prob. 31P Ch. 1.5 - Prob. 32P Ch. 1.5 - Prob. 33P Ch. 1.5 - Prob. 34P Ch. 1.5 - Prob. 35P Ch. 1.5 - Prob. 36P Ch. 1.5 - Prob. 37P Ch. 1.5 - Prob. 38P Ch. 1.5 - Prob. 39P Ch. 1.5 - 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Show that the substitution...Ch. 1.6 - Prob. 57P Ch. 1.6 - Prob. 58P Ch. 1.6 - Solve the differential equation dydx=xy1x+y+3 by...Ch. 1.6 - Prob. 60P Ch. 1.6 - Prob. 61P Ch. 1.6 - Prob. 62P Ch. 1.6 - Prob. 63P Ch. 1.6 - Prob. 64P Ch. 1.6 - Prob. 65P Ch. 1.6 - Prob. 66P Ch. 1.6 - Prob. 67P Ch. 1.6 - Prob. 68P Ch. 1.6 - Prob. 69P Ch. 1.6 - As in the text discussion, suppose that an...Ch. 1.6 - Prob. 71P Ch. 1.6 - Prob. 72P Ch. 1 - Prob. 1RP Ch. 1 - Prob. 2RP Ch. 1 - Prob. 3RP Ch. 1 - Prob. 4RP Ch. 1 - Prob. 5RP Ch. 1 - Prob. 6RP Ch. 1 - Prob. 7RP Ch. 1 - Prob. 8RP Ch. 1 - Prob. 9RP Ch. 1 - Prob. 10RP Ch. 1 - Prob. 11RP Ch. 1 - Prob. 12RP Ch. 1 - Prob. 13RP Ch. 1 - Prob. 14RP Ch. 1 - Prob. 15RP Ch. 1 - Prob. 16RP Ch. 1 - Prob. 17RP Ch. 1 - Prob. 18RP Ch. 1 - Prob. 19RP Ch. 1 - Prob. 20RP Ch. 1 - Prob. 21RP Ch. 1 - Prob. 22RP Ch. 1 - Prob. 23RP Ch. 1 - Prob. 24RP Ch. 1 - Prob. 25RP Ch. 1 - Prob. 26RP Ch. 1 - Prob. 27RP Ch. 1 - Prob. 28RP Ch. 1 - Prob. 29RP Ch. 1 - Prob. 30RP Ch. 1 - Prob. 31RP Ch. 1 - Prob. 32RP Ch. 1 - Prob. 33RP Ch. 1 - Prob. 34RP Ch. 1 - Prob. 35RP Ch. 1 - Prob. 36RP

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Program Description: Purpose of the problem is to find the time when half of the population heard the rumor.

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Program Description: Purpose of the problem is to find the time when half of the population heard the rumor.

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Chapter 1 Solutions