Program Explanation Given information: The differential equation is d y d x = − 3 x 2 + 2 y 2 4 x y . Explanation: The given differential equation can be solved by the method of exact differential equation and by homogeneous form. The given differential equation can be written as, 4 x y d y = − ( 3 x 2 + 2 y 2 ) d x ( 3 x 2 + 2 y 2 ) d x + 4 x y d y = 0 The general form of exact differential equation is, M ( x , y ) d x + N ( x , y ) d y = 0 The above differential equation is exact if and only if the below condition satisfies, ∂ M d y = ∂ N ∂ x ....... (1) Compare the given differential equation with the general differential equation to obtain the value of M ( x , y ) and N ( x , y ) as, M ( x , y ) = 3 x 2 + 2 y 2 N ( x , y ) = 4 x y Substitute 3 x 2 + 2 y 2 for M and 4 x y for N in equation (1) as, ∂ ∂ y ( 3 x 2 + 2 y 2 ) = ? ∂ ∂ x ( 4 x y ) 0 + 4 y = ? 4 y ⋅ 1 4 y = 4 y Thus, the given differential equation is exact. The value of M ( x , y ) can be written as, M ( x , y ) = ∂ F ∂ x The value of F ( x , y ) can be obtained if both the sides of above equation are integrated with respect to x as, ∫ M ( x , y ) d x = F ( x , y ) Substitute 3 x 2 + 2 y 2 in for M ( x , y ) in above equation as, F ( x , y ) = ∫ ( 3 x 2 + 2 y 2 ) d x = 3 ⋅ x 3 3 + 2 y 2 ⋅ x + g ( y ) = x 3 + 2 x y 2 + g ( y ) Now, differentiate the above equation with respect to y , to obtain the value of N ( x , y ) as, N ( x , y ) = ∂ F ∂ y = ∂ ∂ y ( x 3 + 2 x y 2 + g ( y ) ) = 0 + 2 x ⋅ 2 y + g ′ ( y ) = 4 x y + g ′ ( y ) Substitute 4 x y for N ( x , y ) in above equation as, 4 x y = 4 x y + g ′ ( y ) g ′ ( y ) = 0 Integrate the above equation to obtain the value of g ( y ) as, ∫ g ′ ( y ) d y = ∫ 0 d y g ( y ) = 0 + c = c Substitute c for g ( y ) in the value of F ( x , y ) as, F ( x , y ) = x 3 + 2 x y 2 + c Therefore, the solution of the given differential equation is, x 3 + 2 x y 2 = C Here, C is the constant of integration and absorbed the constant c

Differential Equations: Computing and Modeling (5th Edition), Edwards, Penney & Calvis

5th Edition

ISBN: 9780321816252

Author: C. Henry Edwards, David E. Penney, David Calvis

Publisher: PEARSON

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Chapter 1, Problem 33RP

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Program Description: Purpose of problem is to derive general solutions of the differential equation dydx=−3x2+2y24xy in two different ways.

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Chapter 1, Problem 32RP

Chapter 1, Problem 34RP

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Chapter 1 Solutions

Differential Equations: Computing and Modeling (5th Edition), Edwards, Penney & Calvis

Ch. 1.1 - Prob. 1P Ch. 1.1 - Prob. 2P Ch. 1.1 - Prob. 3P Ch. 1.1 - Prob. 4P Ch. 1.1 - Prob. 5P Ch. 1.1 - Prob. 6P Ch. 1.1 - Prob. 7P Ch. 1.1 - Prob. 8P Ch. 1.1 - Prob. 9P Ch. 1.1 - Prob. 10P

Ch. 1.1 - Prob. 11P Ch. 1.1 - Prob. 12P Ch. 1.1 - Prob. 13P Ch. 1.1 - Prob. 14P Ch. 1.1 - Prob. 15P Ch. 1.1 - Prob. 16P Ch. 1.1 - Prob. 17P Ch. 1.1 - Prob. 18P Ch. 1.1 - Prob. 19P Ch. 1.1 - Prob. 20P Ch. 1.1 - Prob. 21P Ch. 1.1 - Prob. 22P Ch. 1.1 - Prob. 23P Ch. 1.1 - Prob. 24P Ch. 1.1 - Prob. 25P Ch. 1.1 - Prob. 26P Ch. 1.1 - Prob. 27P Ch. 1.1 - Prob. 28P Ch. 1.1 - Prob. 29P Ch. 1.1 - Prob. 30P Ch. 1.1 - Prob. 31P Ch. 1.1 - Prob. 32P Ch. 1.1 - Prob. 33P Ch. 1.1 - Prob. 34P Ch. 1.1 - Prob. 35P Ch. 1.1 - Prob. 36P Ch. 1.1 - Prob. 37P Ch. 1.1 - Prob. 38P Ch. 1.1 - Prob. 39P Ch. 1.1 - Prob. 40P Ch. 1.1 - Prob. 41P Ch. 1.1 - Prob. 42P Ch. 1.1 - Prob. 43P Ch. 1.1 - Prob. 44P Ch. 1.1 - Prob. 45P Ch. 1.1 - Prob. 46P Ch. 1.1 - Prob. 47P Ch. 1.1 - Prob. 48P Ch. 1.2 - Prob. 1P Ch. 1.2 - Prob. 2P Ch. 1.2 - Prob. 3P Ch. 1.2 - Prob. 4P Ch. 1.2 - In Problems 1 through 10, find a function y=f(x)...Ch. 1.2 - Prob. 6P Ch. 1.2 - Prob. 7P Ch. 1.2 - Prob. 8P Ch. 1.2 - Prob. 9P Ch. 1.2 - Prob. 10P Ch. 1.2 - Prob. 11P Ch. 1.2 - Prob. 12P Ch. 1.2 - Prob. 13P Ch. 1.2 - Prob. 14P Ch. 1.2 - Prob. 15P Ch. 1.2 - Prob. 16P Ch. 1.2 - Prob. 17P Ch. 1.2 - Prob. 18P Ch. 1.2 - Prob. 19P Ch. 1.2 - Prob. 20P Ch. 1.2 - Prob. 21P Ch. 1.2 - Prob. 22P Ch. 1.2 - Prob. 23P Ch. 1.2 - A ball is dropped from the top of a building 400...Ch. 1.2 - Prob. 25P Ch. 1.2 - Prob. 26P Ch. 1.2 - Prob. 27P Ch. 1.2 - Prob. 28P Ch. 1.2 - A diesel car gradually speeds up so that for the...Ch. 1.2 - Prob. 30P Ch. 1.2 - Prob. 31P Ch. 1.2 - Prob. 32P Ch. 1.2 - On the planet Gzyx, a ball dropped from a height...Ch. 1.2 - Prob. 34P Ch. 1.2 - Prob. 35P Ch. 1.2 - Prob. 36P Ch. 1.2 - Prob. 37P Ch. 1.2 - Prob. 38P Ch. 1.2 - If a=0.5mi and v0=9mi/h as in Example 4, what must...Ch. 1.2 - Prob. 40P Ch. 1.2 - Prob. 41P Ch. 1.2 - Prob. 42P Ch. 1.2 - Prob. 43P Ch. 1.2 - Prob. 44P Ch. 1.3 - Prob. 1P Ch. 1.3 - Prob. 2P Ch. 1.3 - Prob. 3P Ch. 1.3 - Prob. 4P Ch. 1.3 - Prob. 5P Ch. 1.3 - Prob. 6P Ch. 1.3 - Prob. 7P Ch. 1.3 - Prob. 8P Ch. 1.3 - Prob. 9P Ch. 1.3 - Prob. 10P Ch. 1.3 - Prob. 11P Ch. 1.3 - Prob. 12P Ch. 1.3 - Prob. 13P Ch. 1.3 - Prob. 14P Ch. 1.3 - Prob. 15P Ch. 1.3 - Prob. 16P Ch. 1.3 - Prob. 17P Ch. 1.3 - Prob. 18P Ch. 1.3 - Prob. 19P Ch. 1.3 - Prob. 20P Ch. 1.3 - Prob. 21P Ch. 1.3 - Prob. 22P Ch. 1.3 - Prob. 23P Ch. 1.3 - Prob. 24P Ch. 1.3 - Prob. 25P Ch. 1.3 - Prob. 26P Ch. 1.3 - Prob. 27P Ch. 1.3 - Prob. 28P Ch. 1.3 - Verify that if c is a constant, then the function...Ch. 1.3 - Prob. 30P Ch. 1.3 - Prob. 31P Ch. 1.3 - Prob. 32P Ch. 1.3 - Prob. 33P Ch. 1.3 - (a) Use the direction field of Problem 5 to...Ch. 1.3 - Prob. 35P Ch. 1.4 - Prob. 1P Ch. 1.4 - Prob. 2P Ch. 1.4 - Prob. 3P Ch. 1.4 - Prob. 4P Ch. 1.4 - Prob. 5P Ch. 1.4 - Prob. 6P Ch. 1.4 - Prob. 7P Ch. 1.4 - Prob. 8P Ch. 1.4 - Prob. 9P Ch. 1.4 - Prob. 10P Ch. 1.4 - Prob. 11P Ch. 1.4 - Prob. 12P Ch. 1.4 - Prob. 13P Ch. 1.4 - Prob. 14P Ch. 1.4 - Prob. 15P Ch. 1.4 - Prob. 16P Ch. 1.4 - Prob. 17P Ch. 1.4 - Prob. 18P Ch. 1.4 - Prob. 19P Ch. 1.4 - Prob. 20P Ch. 1.4 - Prob. 21P Ch. 1.4 - Prob. 22P Ch. 1.4 - Prob. 23P Ch. 1.4 - Prob. 24P Ch. 1.4 - Prob. 25P Ch. 1.4 - Prob. 26P Ch. 1.4 - Prob. 27P Ch. 1.4 - Prob. 28P Ch. 1.4 - Prob. 29P Ch. 1.4 - Prob. 30P Ch. 1.4 - Prob. 31P Ch. 1.4 - Prob. 32P Ch. 1.4 - (Population growth) A certain city had a...Ch. 1.4 - Prob. 34P Ch. 1.4 - Prob. 35P Ch. 1.4 - (Radiocarbon dating) Carbon taken from a purported...Ch. 1.4 - Prob. 37P Ch. 1.4 - (Continuously compounded interest) Suppose that...Ch. 1.4 - Prob. 39P Ch. 1.4 - Prob. 40P Ch. 1.4 - Prob. 41P Ch. 1.4 - Prob. 42P Ch. 1.4 - Prob. 43P Ch. 1.4 - Prob. 44P Ch. 1.4 - Prob. 45P Ch. 1.4 - Prob. 46P Ch. 1.4 - Prob. 47P Ch. 1.4 - Prob. 48P Ch. 1.4 - Prob. 49P Ch. 1.4 - The amount A (t ) of atmospheric pollutants in a...Ch. 1.4 - An accident at a nuclear power plant has left the...Ch. 1.4 - Prob. 52P Ch. 1.4 - Prob. 53P Ch. 1.4 - Prob. 54P Ch. 1.4 - Prob. 55P Ch. 1.4 - Prob. 56P Ch. 1.4 - Prob. 57P Ch. 1.4 - Prob. 58P Ch. 1.4 - Prob. 59P Ch. 1.4 - Prob. 60P Ch. 1.4 - A spherical tank of radius 4 ft is full of water...Ch. 1.4 - Prob. 62P Ch. 1.4 - Prob. 63P Ch. 1.4 - (The clepsydra, or water clock) A 12 h water clock...Ch. 1.4 - Prob. 65P Ch. 1.4 - Prob. 66P Ch. 1.4 - Prob. 67P Ch. 1.4 - Figure 1.4.11 shows a bead sliding down a...Ch. 1.4 - Prob. 69P Ch. 1.5 - Prob. 1P Ch. 1.5 - Prob. 2P Ch. 1.5 - Prob. 3P Ch. 1.5 - Prob. 4P Ch. 1.5 - Prob. 5P Ch. 1.5 - Prob. 6P Ch. 1.5 - Prob. 7P Ch. 1.5 - Prob. 8P Ch. 1.5 - Prob. 9P Ch. 1.5 - Prob. 10P Ch. 1.5 - Prob. 11P Ch. 1.5 - Prob. 12P Ch. 1.5 - Prob. 13P Ch. 1.5 - Prob. 14P Ch. 1.5 - Prob. 15P Ch. 1.5 - Prob. 16P Ch. 1.5 - Prob. 17P Ch. 1.5 - Prob. 18P Ch. 1.5 - Prob. 19P Ch. 1.5 - Prob. 20P Ch. 1.5 - Prob. 21P Ch. 1.5 - Prob. 22P Ch. 1.5 - Prob. 23P Ch. 1.5 - Prob. 24P Ch. 1.5 - Prob. 25P Ch. 1.5 - Prob. 26P Ch. 1.5 - Prob. 27P Ch. 1.5 - Prob. 28P Ch. 1.5 - Prob. 29P Ch. 1.5 - Prob. 30P Ch. 1.5 - Prob. 31P Ch. 1.5 - Prob. 32P Ch. 1.5 - Prob. 33P Ch. 1.5 - Prob. 34P Ch. 1.5 - Prob. 35P Ch. 1.5 - Prob. 36P Ch. 1.5 - Prob. 37P Ch. 1.5 - Prob. 38P Ch. 1.5 - Prob. 39P Ch. 1.5 - Prob. 40P Ch. 1.5 - Prob. 41P Ch. 1.5 - Prob. 42P Ch. 1.5 - Figure 1.5.7 shows a slope field and typical...Ch. 1.5 - Prob. 44P Ch. 1.5 - Prob. 45P Ch. 1.5 - Prob. 46P Ch. 1.6 - Prob. 1P Ch. 1.6 - Prob. 2P Ch. 1.6 - Prob. 3P Ch. 1.6 - Prob. 4P Ch. 1.6 - Prob. 5P Ch. 1.6 - Prob. 6P Ch. 1.6 - Prob. 7P Ch. 1.6 - Prob. 8P Ch. 1.6 - Prob. 9P Ch. 1.6 - Prob. 10P Ch. 1.6 - Prob. 11P Ch. 1.6 - Prob. 12P Ch. 1.6 - Prob. 13P Ch. 1.6 - Prob. 14P Ch. 1.6 - Prob. 15P Ch. 1.6 - Prob. 16P Ch. 1.6 - Prob. 17P Ch. 1.6 - Prob. 18P Ch. 1.6 - Prob. 19P Ch. 1.6 - Prob. 20P Ch. 1.6 - Prob. 21P Ch. 1.6 - Prob. 22P Ch. 1.6 - Prob. 23P Ch. 1.6 - Prob. 24P Ch. 1.6 - Prob. 25P Ch. 1.6 - Prob. 26P Ch. 1.6 - Prob. 27P Ch. 1.6 - Prob. 28P Ch. 1.6 - Prob. 29P Ch. 1.6 - Prob. 30P Ch. 1.6 - Prob. 31P Ch. 1.6 - Prob. 32P Ch. 1.6 - Prob. 33P Ch. 1.6 - Prob. 34P Ch. 1.6 - Prob. 35P Ch. 1.6 - Prob. 36P Ch. 1.6 - Prob. 37P Ch. 1.6 - Prob. 38P Ch. 1.6 - Prob. 39P Ch. 1.6 - Prob. 40P Ch. 1.6 - Prob. 41P Ch. 1.6 - Prob. 42P Ch. 1.6 - Prob. 43P Ch. 1.6 - Prob. 44P Ch. 1.6 - Prob. 45P Ch. 1.6 - Prob. 46P Ch. 1.6 - Prob. 47P Ch. 1.6 - Prob. 48P Ch. 1.6 - Prob. 49P Ch. 1.6 - Prob. 50P Ch. 1.6 - Prob. 51P Ch. 1.6 - Prob. 52P Ch. 1.6 - Prob. 53P Ch. 1.6 - Prob. 54P Ch. 1.6 - Prob. 55P Ch. 1.6 - Suppose that n0 and n1. Show that the substitution...Ch. 1.6 - Prob. 57P Ch. 1.6 - Prob. 58P Ch. 1.6 - Solve the differential equation dydx=xy1x+y+3 by...Ch. 1.6 - Prob. 60P Ch. 1.6 - Prob. 61P Ch. 1.6 - Prob. 62P Ch. 1.6 - Prob. 63P Ch. 1.6 - Prob. 64P Ch. 1.6 - Prob. 65P Ch. 1.6 - Prob. 66P Ch. 1.6 - Prob. 67P Ch. 1.6 - Prob. 68P Ch. 1.6 - Prob. 69P Ch. 1.6 - As in the text discussion, suppose that an...Ch. 1.6 - Prob. 71P Ch. 1.6 - Prob. 72P Ch. 1 - Prob. 1RP Ch. 1 - Prob. 2RP Ch. 1 - Prob. 3RP Ch. 1 - Prob. 4RP Ch. 1 - Prob. 5RP Ch. 1 - Prob. 6RP Ch. 1 - Prob. 7RP Ch. 1 - Prob. 8RP Ch. 1 - Prob. 9RP Ch. 1 - Prob. 10RP Ch. 1 - Prob. 11RP Ch. 1 - Prob. 12RP Ch. 1 - Prob. 13RP Ch. 1 - Prob. 14RP Ch. 1 - Prob. 15RP Ch. 1 - Prob. 16RP Ch. 1 - Prob. 17RP Ch. 1 - Prob. 18RP Ch. 1 - Prob. 19RP Ch. 1 - Prob. 20RP Ch. 1 - Prob. 21RP Ch. 1 - Prob. 22RP Ch. 1 - Prob. 23RP Ch. 1 - Prob. 24RP Ch. 1 - Prob. 25RP Ch. 1 - Prob. 26RP Ch. 1 - Prob. 27RP Ch. 1 - Prob. 28RP Ch. 1 - Prob. 29RP Ch. 1 - Prob. 30RP Ch. 1 - Prob. 31RP Ch. 1 - Prob. 32RP Ch. 1 - Prob. 33RP Ch. 1 - Prob. 34RP Ch. 1 - Prob. 35RP Ch. 1 - Prob. 36RP

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Program Description: Purpose of problem is to derive general solutions of the differential equation d y d x = − 3 x 2 + 2 y 2 4 x y in two different ways.

Solution Summary: The author explains that the given differential equation can be solved by the method of exact and by homogeneous form.

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Program Description: Purpose of problem is to derive general solutions of the differential equation dydx=−3x2+2y24xy in two different ways.

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Chapter 1 Solutions