Chapter 14, Problem 39PE

(a)

Interpretation Introduction

Interpretation:

Molality of solution prepared by dissolution of $2.0\text{ mol HCl}$ in $175\text{ g}$ of water has to be determined.

Concept Introduction:

Molality is amount of solute present in one kilogram of solvent. Expression to calculate molality of solution is as follows:

  $\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass }\left(\text{kg}\right)\text{of solvent}}$

(b)

Interpretation Introduction

Interpretation:

Molality of solution prepared by dissolution of $14.5{\text{ g C}}_{12}{\text{H}}_{22}{\text{O}}_{11}$ in $\text{550}\text{.0 g}$ of water has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Molality of solution prepared by dissolution of $25.2{\text{ mL CH}}_3\text{OH}$ in $\text{595 g}$ of ${\text{CH}}_3{\text{CH}}_2\text{OH}$ has to be determined.

Concept Introduction:

Refer to part (a).