EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119227946
Author: Willard
Publisher: VST
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Chapter 14, Problem 79AE
Interpretation Introduction
Interpretation:
Whether
Concept Introduction:
Stoichiometry describes quantitative relationships between reactants and products in any
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Sodium hydrogen carbonate (NaHCO3), also known as sodium bicarbonate or "baking soda", can be used to relieve acid
indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid
(HCI), which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO3 neutralizes
excess HCl through this reaction:
HCl(aq) + NaHCO3(aq) → NaCl(aq) + H₂O(1) + CO₂(g)
-
A
The CO₂ gas produced is what makes you burp after drinking the solution.
ol
Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 200. mL of a 0.067 M HCl
solution. What mass of NaHCO3 would he need to ingest to neutralize this much HCl ? Round your answer to 2 significant
digits.
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5.0
x10
X
?
5
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When a person’s stomach oversecretes gastric juices containing hydrochloric acid, the person treats it with antacids. Some antacids in the market are made up of aluminum hydroxide (Al(OH)3), milk of magnesia (Mg(OH)2), and sodium bicarbonate (NaHCO3). Which of the three antacids is more effective per gram?
Note: the effective antacids can be determined by computing for thehighest number of moles of hydrochloric acids that react with the givenantacids.
Al(OH)3 + 3HCl → AlCl3 + 3H2OMg(OH)2 + 2HCl → MgCl2 + 2H2ONaHCO3 + HCl → NaCl + H2O + CO2
Please answer question 17 Part A
Chapter 14 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 14.1 - Prob. 14.1PCh. 14.2 - Prob. 14.2PCh. 14.3 - Prob. 14.3PCh. 14.4 - Prob. 14.4PCh. 14.4 - Prob. 14.5PCh. 14.4 - Prob. 14.6PCh. 14.4 - Prob. 14.7PCh. 14.4 - Prob. 14.8PCh. 14.4 - Prob. 14.9PCh. 14.4 - Prob. 14.10P
Ch. 14.5 - Prob. 14.11PCh. 14.5 - Prob. 14.12PCh. 14 - Prob. 1RQCh. 14 - Prob. 2RQCh. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQCh. 14 - Prob. 6RQCh. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - Prob. 9RQCh. 14 - Prob. 10RQCh. 14 - Prob. 11RQCh. 14 - Prob. 12RQCh. 14 - Prob. 13RQCh. 14 - Prob. 14RQCh. 14 - Prob. 15RQCh. 14 - Prob. 16RQCh. 14 - Prob. 17RQCh. 14 - Prob. 18RQCh. 14 - Prob. 19RQCh. 14 - Prob. 20RQCh. 14 - Prob. 21RQCh. 14 - Prob. 22RQCh. 14 - Prob. 23RQCh. 14 - Prob. 24RQCh. 14 - Prob. 25RQCh. 14 - Prob. 26RQCh. 14 - Prob. 27RQCh. 14 - Prob. 28RQCh. 14 - Prob. 29RQCh. 14 - Prob. 30RQCh. 14 - Prob. 31RQCh. 14 - Prob. 32RQCh. 14 - Prob. 33RQCh. 14 - Prob. 34RQCh. 14 - Prob. 35RQCh. 14 - Prob. 37RQCh. 14 - Prob. 38RQCh. 14 - Prob. 39RQCh. 14 - Prob. 40RQCh. 14 - Prob. 41RQCh. 14 - Prob. 42RQCh. 14 - Prob. 1PECh. 14 - Prob. 2PECh. 14 - Prob. 3PECh. 14 - Prob. 4PECh. 14 - Prob. 5PECh. 14 - Prob. 6PECh. 14 - Prob. 7PECh. 14 - Prob. 8PECh. 14 - Prob. 9PECh. 14 - Prob. 10PECh. 14 - Prob. 11PECh. 14 - Prob. 12PECh. 14 - Prob. 13PECh. 14 - Prob. 14PECh. 14 - Prob. 15PECh. 14 - Prob. 16PECh. 14 - Prob. 17PECh. 14 - Prob. 18PECh. 14 - Prob. 19PECh. 14 - Prob. 20PECh. 14 - Prob. 21PECh. 14 - Prob. 22PECh. 14 - Prob. 23PECh. 14 - Prob. 24PECh. 14 - Prob. 25PECh. 14 - Prob. 26PECh. 14 - Prob. 27PECh. 14 - Prob. 28PECh. 14 - Prob. 29PECh. 14 - Prob. 30PECh. 14 - Prob. 31PECh. 14 - Prob. 32PECh. 14 - Prob. 33PECh. 14 - Prob. 34PECh. 14 - Prob. 35PECh. 14 - Prob. 36PECh. 14 - Prob. 37PECh. 14 - Prob. 38PECh. 14 - Prob. 39PECh. 14 - Prob. 40PECh. 14 - Prob. 41PECh. 14 - Prob. 42PECh. 14 - Prob. 44PECh. 14 - Prob. 45PECh. 14 - Prob. 46PECh. 14 - Prob. 47PECh. 14 - Prob. 48PECh. 14 - Prob. 49PECh. 14 - Prob. 50PECh. 14 - Prob. 51PECh. 14 - Prob. 52PECh. 14 - Prob. 53AECh. 14 - Prob. 54AECh. 14 - Prob. 55AECh. 14 - Prob. 56AECh. 14 - Prob. 57AECh. 14 - Prob. 58AECh. 14 - Prob. 59AECh. 14 - Prob. 60AECh. 14 - Prob. 61AECh. 14 - Prob. 62AECh. 14 - Prob. 63AECh. 14 - Prob. 65AECh. 14 - Prob. 66AECh. 14 - Prob. 67AECh. 14 - Prob. 68AECh. 14 - Prob. 69AECh. 14 - Prob. 70AECh. 14 - Prob. 71AECh. 14 - Prob. 72AECh. 14 - Prob. 73AECh. 14 - Prob. 74AECh. 14 - Prob. 75AECh. 14 - Prob. 76AECh. 14 - Prob. 77AECh. 14 - Prob. 78AECh. 14 - Prob. 79AECh. 14 - Prob. 80AECh. 14 - Prob. 81AECh. 14 - Prob. 82AECh. 14 - Prob. 83AECh. 14 - Prob. 84AECh. 14 - Prob. 85AECh. 14 - Prob. 86AECh. 14 - Prob. 87AECh. 14 - Prob. 88AECh. 14 - Prob. 90AECh. 14 - Prob. 91AECh. 14 - Prob. 92AECh. 14 - Prob. 93AECh. 14 - Prob. 94AECh. 14 - Prob. 95AECh. 14 - Prob. 96AECh. 14 - Prob. 97AECh. 14 - Prob. 98AECh. 14 - Prob. 99CECh. 14 - Prob. 100CECh. 14 - Prob. 102CECh. 14 - Prob. 103CECh. 14 - Prob. 104CECh. 14 - Prob. 105CE
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- Reactions represented by the following equations take place in water solutions. Write each molecular equation in total ionic form, then identify spectator ions and write the equations in net ionic form. Solids that do not dissolve are designated by s, gases that do not dissolve are designated by g, and substances that dissolve but do not dissociate appear in blue. a. H2O(l)+Na2SO3(aq)+SO2(aq)2NaHSO3(aq) b. 3Cu(s)+8HNO3(aq)3Cu(NO3)2(aq)+2NO(g)+4H2O(l) c. 2HCl(aq)+CaO(s)CaCl2(aq)+H2O(l) d. CaCO3(s)+2HCl(aq)CaCl2(aq)+CO2(aq)+H2O(l) e. MnO2(s)+4HCl(aq)MnCl2(aq)+Cl2(aq)+2H2O(l) f. 2AgNO3(aq)+Cu(s)Cu(NO3)2(aq)+2Ag(s)arrow_forwardDraw the contents of a beaker of water that contains dissolved forms of the following (draw only the substances added to the water): (a) potassium chloride (b) barium hydroxide (c) molecular oxygen, O2arrow_forwardWhat volume of 0.250 M HCI is required to neutralize each of the following solutions? a. 25.0 mL of 0.103 M sodium hydroxide, NaOH b. 50.0 mL of 0.00501 M calcium hydroxide, Ca(OH)2 c. 20.0 mL of 0.226 M ammonia, NH3 d. 15.0 mL of 0.0991 M potassium hydroxide, KOHarrow_forward
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