Chapter 14, Problem 29PE

(a)

Interpretation Introduction

Interpretation:

Volume of concentrated $\text{15 }M{\text{ H}}_{\text{3}}{\text{PO}}_{\text{4}}$ required to prepare $750\text{ mL}$ of $\text{3}\text{.0 }M{\text{ H}}_{\text{3}}{\text{PO}}_{\text{4}}$ has to be determined.

Concept Introduction:

Molarity is amount of solute present in $1\text{ L}$ of solution. Expression for molarity equation is as follows:

  $M_1{V}_1=M_2{V}_2$        (1)

Here,

$M_1$ is molarity of dilute solution.

$V_1$ is volume of dilute solution.

$M_2$ is molarity of concentrated solution.

$V_2$ is volume of concentrated solution.

(b)

Interpretation Introduction

Interpretation:

Volume of concentrated $\text{16 }M{\text{ HNO}}_{\text{3}}$ required to prepare $250\text{ mL}$ of $\text{0}\text{.50 }M{\text{ HNO}}_{\text{3}}$ has to be determined.

Concept Introduction:

Refer to part (a).