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Interpretation:
The difference in structure between ionic solids and molecular solids have to be described. The fundamental particles in each solid have to be explained. Two examples of each of these two solids have to be given and the individual particles that make up the solids have to be indicated.
Concept Introduction:
Generally ,solids are two types-
- Crystalline solids
- Amorphous solids
Crystalline solids are solid compounds with highly ordered structure of the constituents (atoms, molecules or ions). The example of crystalline solids are diamond, quartz, etc.
Amorphous solids are the solid not having definite size and shape. Amorphous solids are not arranged in regular or ordered form.
Crystalline solids are solid compounds with highly ordered structure of the constituents (atoms, molecules or ions). Depending on the constituents (atoms, molecules or ions), the crystalline solids are classified in three types-
Answer to Problem 35A
Intermolecular attractive forces that held the constituents together inside the solids is the main characteristic which differs in different crystalline solids.
Ionic solids consist of ions (cations and anions). The ions in an ionic solid are held together by electrostatic attraction between two oppositely charged ions. Whereas molecular solids consist of molecules. The molecules in a molecular solid are held together by weak Van der Waals forces.
The fundamental particles in ionic solid are ions and the fundamental particles in molecular solid are molecules.
Two examples of ionic solids are-
- NaCl which contains Na+ and Cl- ions
- KNO3 which contains K+ and NO3- ions.
Two examples of molecular solids are-
1. Ice which contains H2O molecules.
2. Dry ice which contains CO2 molecules.
Explanation of Solution
Intermolecular attractive forces that held the constituents together inside the solids is the main characteristic which differs in different crystalline solids.
Ionic solids consist of ions (cations and anions). The ions in an ionic solid are held together by electrostatic attraction between two oppositely charged ions. Whereas molecular solids consist of molecules. The molecules in a molecular solid are held together by weak Van der Waals forces.
The fundamental particles in ionic solid are ions and the fundamental particles in molecular solid are molecules.
Two examples of ionic solids are-
3. NaCl which contains Na+ and Cl- ions
4. KNO3 which contains K+ and NO3- ions.
Two examples of molecular solids are-
3. Ice which contains H2O molecules.
4. Dry ice which contains CO2 molecules.
Chapter 14 Solutions
World of Chemistry
- Please help, this is all the calculations i got!!! I will rate!!!Approx mass of KMnO in vial: 3.464 4 Moss of beaker 3×~0. z Nax200: = 29.9219 Massof weacerv after remosimgain N2C2O4. Need to fill in all the missing blanks. ง ง Approx mass of KMnO4 in vials 3.464 Mass of beaker + 3x ~0-304: 29.9219 2~0.20 Miss of beaker + 2x- 29.7239 Mass of beaker + 1x~0.2g Naz (204 29-5249 Mass of beaver after removing as qa Na₂ C₂O T1 T2 T3 Final Buiet reading Initial butet reading (int)) Hass of NaOr used for Titration -reading (mL) calculation Results: 8.5ml 17mL 27.4mL Oml Om Oml T1 T2 T3 Moles of No CO Moles of KMO used LOF KM. O used Molenty of KMNO Averagem Of KMOWLarrow_forwardDraw the skeletal ("line") structure of 2-hydroxy-4-methylpentanal. Click and drag to start drawing a structure. Xarrow_forwardDetermine whether the following molecule is a hemiacetal, acetal, or neither and select the appropriate box below. Also, highlight the hemiacetal or acetal carbon if there is one. hemiacetal acetal Oneither OHarrow_forward
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- -AG|F=2E|V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: Acidic solution -0.93 +0.38 -0.51 -0.06 H3PO4 →H4P206 H3PO3 H3PO2 → P→ PH3 -0.28 -0.50 → -0.50 Basic solution 3-1.12 -1.57 -2.05 -0.89 PO HPO →→H2PO2 P PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P2O6 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH, 0.0 -0.5- 2 3 9 3 -1.5 -2.0 Pa H,PO H,PO H,PO -3 -1 0 2 4 Oxidation state, N 2 b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) c) Elemental phosphorus tends to disproportionate under basic conditions. Use data in…arrow_forwardThese two reactions appear to start with the same starting materials but result in different products. How do the chemicals know which product to form? Are both products formed, or is there some information missing that will direct them a particular way?arrow_forwardWhat would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Priva ×arrow_forward
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