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Concept explainers
In Ex. 14-5 use nitrided grade 1 steel (4140) which produces Brinell hardnesses of 250 core and 500 at the surface (case). Use the upper fatigue curves on Figs. 14-14 and 14-15. Estimate the power capacity of the mesh with factors of safety of SF = SH = 1.
EXAMPLE 14-5 A 17-tooth 20° normal pitch-angle helical pinion with a right-hand helix angle of 30° rotates at 1800 rev/min when transmitting 4 lip to a 52-tooth helical gear. The normal diametral pitch is 10 teeth/in. the face width is 1.5 in, and the set has a quality number of 6. The gears are straddle-mounted with bearings immediately adjacent. The pinion and gear are made from a through-hardened steel with surface and core hardnesses of 240 Brinell on the pinion and surface and core hardnesses of 200 Brinell on the gear. The transmission is smooth, connecting an electric motor and a centrifugal pump. Assume a pinion life of 108 cycles and a reliability of 0.9 and use the upper curves in Figs. 14-14 and 14-15.
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Chapter 14 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
- FEAarrow_forwardHELP?arrow_forwardTrue and False Indicate if each statement is true or false. T/F 1. Rule #1 protects the function of assembly. T/F 2. One of the fundamental dimensioning rules requires all dimensions apply in the free-state condition for rigid parts. T/F 3. The fundamental dimensioning rules that apply on a drawing must be listed in the general notes. T/F 4. Where Rule #1 applies to a drawing, it limits the form of every feature of size on the drawing. T/F 5. Rule #1 limits the variation between features of size on a part. T/F 6. The designer must specify on the drawing which features of size use Rule #1. T/F T/F T/F 7. Rule #1 applies to nonrigid parts (in the unrestrained state). 8. A GO gage is a fixed-limit gage. 9. Rule #1 requires that the form of an individual regular feature of size is controlled by its limits of sizearrow_forward
- نصاف Sheet Asteel bar of rectangular cross section with dimension Shown in fig. below. This bar is as Connected toawell. Using welded Join a long the sides als only find the weld size (h). Where: Tall = 35 MN/M² F=213.30 answer/h= 4.04 ☐ Yomm Soomm 100mmarrow_forwardPlease also draw the FBDsarrow_forwardDesign Description: Fresh water tank, immersed in an oil tank.a) Water tank:a. Shape: Cylindricalb. Radius: 1 meterc. Height: 3 metersd. Bottom airlock: 0.2m x 0.2m. b) Oil tank:a. Shape: cylindricalb. Radius: 4 metersc. Oil density: 850 kg/m³ Determine:a) The pressure experienced by an airlock at the bottom of the tank with water.b) The force and direction necessary to open the lock, suppose the lock weighs 20 Newtons, suppose the lock opens outwards. The image is for illustrative purposes, the immersed cylinder does not reach the bottomarrow_forward
- Need help!arrow_forwardneed help understanding?arrow_forward%94 KB/S Find : 1. dynamic load on each bearing due to the out-of-balance couple; and 2. kinetic energy of the complete assembly. [Ans. 6.12 kg: 8.7 N-m] L 2. 3. 4. 5. 1. 2. 5. DO YOU KNOW? Why is balancing of rotating parts necessary for high speed engines? Explain clearly the terms "static balancing' and 'dynamic balancing'. State the necessary conditions to achieve them. Discuss how a single revolving mass is balanced by two masses revolving in different planes. Chapter 21: Balancing of Rotating Masses .857 Explain the method of balancing of different masses revolving in the same plane. How the different masses rotating in different planes are balanced? OBJECTIVE TYPE QUESTIONS The balancing of rotating and reciprocating parts of an engine is necessary when it runs at (a) slow speed (b) medium speed (c) high speed A disturbing mass, attached to a rotating shaft may be balanced by a single mass m, attached in the same plane of rotation as that of my such that (a) (b) F For static…arrow_forward
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