Concept explainers
A researcher has a Trp auxotrophic strain of E. coli with a mutation in a single gene. To identify that mutant
gene, she uses a genomic library made from a wild-type version of that same strain to find plasmids that rescue the mutant
of the plasmids contain gene X, while the other four contain gene Y. Our scientist has encountered a
phenomenon called multicopy suppression, related to the fact that plasmids are usually present in several copies per bacterium. Because the genes in the plasmids are present in more than their usual single copy in the
bacterial chromosome, more than the usual amount of Protein X or Protein Y is being produced from the plasmids. Sometimes, overexpression of one protein can rescue the mutant phenotype caused by loss of a
different protein. Suggest at least two ways that our scientist could determine which of the two genes, gene X or gene Y, actually corresponds to the mutant gene causing the Trp phenotype.
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Genetics: From Genes To Genomes (6th International Edition)
- You transform bacteria with a plasmid carrying the ampicillin-resistance gene ampR. How would you determine which bacteria took up the plasmid? O Bacteria containing the plasmid would be able to grow in the absence of ampicillin. O Bacteria containing the plasmid would be able to grow in the presence of ampicillin. O Bacteria containing the plasmid would be able to produce ampicillin. O Ampicillin-resistance is necessary for the plasmid DNA get into the bacteria.arrow_forwardWhen cloning a foreign DNA fragment into a plasmid, it is often useful to insert the fragment at a site that interrupts a selectable marker(such as the tetracycline-resistance gene of pBR322). The loss of function of the interrupted gene can be used to identify clones containing recombinant plasmids with foreign DNA. With a yeast artificial chromosome (YAC) vector, it is not necessary to do this; the researcher can still distinguish vectors that incorporate large foreign DNA fragments from those that do not. How are these recombinant vectors identified?arrow_forwardA plasmid, pUC18, contains the ampicillin-resistance gene, the origin of replication, and the ß - gal gene, which codes for the B-galactosidase protein. This protein can break down the synthetic chemical X-gal, producing a blue product that stains the entire cell blue (but is harmless to the bacteria). At the beginning of the B-gal gene there are several unique restriction sites (some of them are shown in the diagram below). You wish to clone a 1.0-kb Xbal fragment into the pUC18 plasmid, so you cut the plasmid with Xbal and, after removing the enzyme, mix the Xbal-cut plasmid with the 1.0-kb fragment, ligate, and transform competent bacteria. Pati Xbal EcoRI B-gal A Amp ori Figure: pUC18 plasmid map (a) On what medium would you grow your transformed bacteria? (b) Do you expect the bacteria carrying plasmid pUC18 (without the insert) to be blue or white when grown in the presence of X-gal? Explain.arrow_forward
- A) Outline the experimental procedure for cloning a eukaryotic gene and expressing it in E. coli. Focus on the essential steps starting with eukaryotic gene amplification to transformation of E. coli cells B) Explain how insertional inactivation can help you identify the colonies that carry the plasmid with your eukaryotic gene of interest C) Plasmids containing antibiotic resistance genes are widely used in gene cloning and other molecular biology techniques. What would happen if the eukaryotic gene was inserted into an antibiotic resistance gene on the plasmid?arrow_forwardAfter transformation you were asked to grow bacterial cells transformed with plasmid on a plate that had X-gal and ampicillin. X-Gal is often used as in indicator dye, which turns blue when metabolized by B-galactosidase protein and used to test if cloning experiments have worked. [Note look at the vector diagrams carefully] Briefly explain how you would find the bacterial cells that are transformed with the plasmid with the YFG inserted.arrow_forwardIn this western blot, the levels of phosphorylated TBK (PTBK) decrease with increasing amounts/expression of the viral protein (VP). Figure description: Increasing amounts of a plasmid expressing the viral protein (0.5, 1, or 2ug) were cotransfected with TBK1 expression plasmid. Cells were harvested 24 h post-transfection and analyzed for phosphorylated TBK1 (anti- TBK1 Ser172), total TBK1 (anti-TBK1), B-actin (anti-B-actin), and viral protein (anti-VP) expression by Western blot analysis. VP PTBK1 (S172) TBK1 actin Virus proteins O True O Falsearrow_forward
- The transfection reagent used to introduce plasmids to the HEK293 cells was a lipid reagent. Why is lipid utilized for this procedure?arrow_forwardWe transformed E coli cells with a plasmid modified to contain a ‘virulence factor’ which would allow growth on media containing the antibiotic kanamycin (Kan). The plasmid confers constitutive resistance to ampicillin (Amp). Assume you were given competent cells of known transformation efficiency (TE). Assume TE= 1x10[7] (note 10[7] means 10 to the power of 7). You want to have about 1000 colonies on the P-200 plate. How many nanograms of plasmid should you use in the transformation reaction? Select only one answer. 1. 0.05 2. 20.00 3. 0.50 4. 50.00 5. 200.00 6. 5.00arrow_forwardE. coli strains diploid for the lac region were constructed by introducing a plasmid carrying the lac genes. The plasmid carries one copy of the lac region, and the chromosome carries the other copy. The two copies of the lac region have different genotypes, as shown in the chart below. Indicate whether the products of the lacy gene (permease) and the lacZ gene (B-galactosidase) will be inducible, uninducible, or constitutive in each strain (assuming glucose is absent). lac region on plasmid lac region on chromosome permease B-galactosidase I-o+Z+Y- I+o+ Z-Y+ I+o+Z+Y- I+o° Z=Y+ I- oº Z+Y- I+o+ Z-Y+ Is o+ Z+Y- I+o+ Z-Y+ I+ oc Z+Y- IS O+ Z-Y+arrow_forward
- In the formation of recombinant DNA, a restriction endonuclease cuts a bacterial plasmid to give sticky ends. The DNA segments that are to be added to the plasmid are cleaved with the same restriction endonuclease. What aresticky ends and why is it important that the target DNA and the plasmid it will be incorporated into have complementary sticky ends?arrow_forwardA plasmid that is both ampicillin and tetracyclineresistant is cleaved with PstI, which cleaves within theampicillin resistance gene. The cut plasmid is ligated withPstI-digested Drosophila DNA to prepare a genomic library,and the mixture is used to transform E. coli K12. Question: How can you explain the presence of colonies thatare resistant to both antibiotics?arrow_forwardA plasmid contains genes for ampicillin resistance and chloramphenicol resistance and has single sites for Hind III and Eco RI. When genes are inserted into the Eco RI site, transformants are resistant only to ampicillin. In which region is the site for EcoRI located? Group of answer choices within the chloramphenicol gene between the ampicillin and chloramphenicol genes can't be determined within the ampicillin genearrow_forward
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