ou seal a container half-filled with water. Which best describes what occurs in the container?
Water evaporates until the air becomes saturated with water vapor; at this point, no more water evaporates.
Water evaporates until the air becomes overly saturated (supersaturated) with water, and most of this water recondenses; this cycle continues until a certain amount of water vapor is present, and then the cycle ceases.
The water does not evaporate because the container sealed.
Water evaporates, and thou water evaporates and recondenses simultaneously and continuously.
The water evaporates until it is eventually all in vapor form.
stify your choice, and for choices you did not pick, explain what is wrong with them.

Interpretation:
If a container is sealed half filled with water then what will happen must be chosen from the options given.
Concept Introduction:
When any liquid is there in a closed container then vapor accumulates above the liquid.
Answer to Problem 1ALQ
Option a) is correct answer.
Explanation of Solution
Reason for correct option:
When the container is half filed with water then there is vacuum above the water surface. Now to compensate the reduced pressure water stars vaporizing and then the vacuum is saturated with water vapor then no more vaporization takes place further.
Reasons for incorrect options:
Option b) is incorrect as over saturation will not arise. After the air is saturated no more further evaporation takes place.
Option c) is incorrect as it is stating that water will not evaporate due to sealed container.
Option d) is incorrect as it is stating that water evaporates and condenses simultaneously and continuously but it’s not stating about saturation.
Option e) is incorrect as it’s stating that whole water will be converted to vapor which is not possible due to water and water vapor equilibrium.
Want to see more full solutions like this?
Chapter 14 Solutions
Introductory Chemistry: Foundation - Text (Looseleaf)
- The decimolar calomel electrode has a potential of 0.3335 V at 25°C compared to the standard hydrogen electrode. If the standard reduction potential of Hg22+ is 0.7973 V and the solubility product of Hg2Cl2 is 1.2x 10-18, find the activity of the chlorine ion at this electrode.Data: R = 8.314 J K-1 mol-1, F = 96485 C mol-1, T = 298.15 K.arrow_forward2. Add the following group of numbers using the correct number of significant figures for the answer. Show work to earn full credit such as rounding off the answer to the correct number of significant figures. Replace the question marks with the calculated answers or write the calculated answers near the question marks. 10916.345 37.40832 5.4043 3.94 + 0.0426 ? (7 significant figures)arrow_forwardThe emf at 25°C of the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt was 612 mV. When solution X was replaced by normal phosphate buffer solution with a pH of 6.86, the emf was 741 mV. Calculate the pH of solution X.arrow_forward
- Indicate how to calculate the potential E of the reaction Hg2Cl2(s) + 2e ⇄ 2Hg + 2Cl- as a function of the concentration of Cl- ions. Data: the solubility product of Hg2Cl2.arrow_forwardHow can Beer’s Law be used to determine the concentration in a selected food sample. Provide an in-depth discussion and examples of this.arrow_forwardb) H3C- H3C Me CH 3 I HN Me H+arrow_forward
- Using Luther's rule, determine the reference potentials of the electrodes corresponding to the low stability systems Co³+/Co and Cr²+/Cr from the data in the table. Electrodo ΕΝ Co²+/Co Co3+/Co²+ -0,28 +1,808 Cr³+ / Cr -0,508 Cr3+ / Cr²+ -0,41arrow_forwardThe molecule PYRIDINE, 6tt electrons and is there pore aromuntre and is Assigned the Following structure contenus Since aromatk moleculey undergo electrophilic allomatic substitution, Pyridine should undergo The Following reaction + HNO3 12504 a. write all of the possible Mononitration Products that could Result From this roaction Based upon the reaction the reaction mechanism determine which of these producty would be the major Product of the hegetionarrow_forwardUsing Benzene as starting materia Show how each of the Following molecules could Ve synthesked 9. CHI d. 10450 b 0 -50311 ८ City -5034 1-0-650 e NO2arrow_forward
- BA HBr of the fol 1)=MgCI 2) H₂O major NaOEt Ts Cl Py (pyridine) 1) 03 2) Me2S 1arrow_forward4. Provide a clear arrow-pushing mechanism for the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a) NHBoc ⚫OBn HO. H3C CO2CH3 -OBn H3C H3C. H3C. NHBOC CI CO2CH3arrow_forwardDraw structures of the following compounds and identify their role: mCPBA (MCPBA) DMS Py 9-BBN LAH Sia₂BH TsCI PCC t-BuOK LDA MeLi n-BuLi DMSO DMF Sodium Borohydride Lithium DiisopropylAmide 2arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning





