Chapter 14, Problem 14A.8BE

Interpretation Introduction

Interpretation:

The refractive index of a liquid when the polarizability volume of the liquid is $2.2\times {10}^{-30}{\text{m}}^3$ at optical frequencies is to be calculated.

Concept introduction:

When the molecules are polar or extremely polarizable, then the substance has large relative permittivity.  The interaction between the relative permittivity and the molecule’s electrical characteristic is acquired by considering a medium's polarization.  It is expressed by the Debye equation, as shown below.

    $\frac{{\epsilon }_{\text{r}}-1}{{\epsilon }_{\text{r}}+2}=\frac{\rho P_{\text{m}}}{M}$

The polarizability, $\alpha$ is expressed by the formula shown below.

    $\frac{{\epsilon }_{\text{r}}-1}{{\epsilon }_{\text{r}}+2}=\frac{\rho N_{\text{A}}\alpha }{3M{\epsilon }_{\text{ο}}}$