Chapter 14, Problem 14A.6AE

Interpretation Introduction

Interpretation:

The relative permittivity of the liquid chlorine trifluoride having molar polarization $27.18{\text{cm}}^3{\text{mol}}^{-1}$ at $\text{0}{}^{\text{ο}}\text{C}$ is to be calculated.

Concept introduction:

When the molecules are polar or extremely polarizable, then the substance has large relative permittivity.  The interaction between the relative permittivity and the molecule’s electrical characteristic is acquired by considering a medium's polarization.  It is expressed by the Debye equation, as shown below.

    $\frac{{\epsilon }_{\text{r}}-1}{{\epsilon }_{\text{r}}+2}=\frac{\rho P_{\text{m}}}{M}$