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- Reaction of p-cresol with two equivalents of 2-methylprop-1-ene affordsBHT, a preservative with molecular formula C15H24O. BHT gives thefollowing 1H NMR spectral data: 1.4 (singlet, 18 H), 2.27 (singlet, 3 H), 5.0(singlet, 1 H), and 7.0 (singlet, 2 H) ppm. What is the structure of BHT?Draw a stepwise mechanism illustrating how it is formed.arrow_forwardThe compound with the closed formula C4H9Br gives the following 1H NMR data. Write the clear formula of the compound with reasons. 1.0 ppm (triplet, 3 H); 1.7 ppm (dublet, 3H); 1.8 ppm (multiplet, 2H); 4.2 ppm (multiplet, 1H)arrow_forwardReaction between this aldehyde and ketone in base gives a compound A with the proton NMR spectrum: ô 1.10 (9H, s), 1.17 (9H, s), 6.4 (1H, d, J 15), and 7.0 (1H, d, J 15). What is its structure? (Don't forget stereochemistry!). When this compound reacts with HBr it gives compound B with this NMR spectrum: õu 1.08 (9H, s), 1.13 (9H, s), 2.71 (1H, dd, J 1.9, 17.7), 3.25 (dd, J10.0, 17.7), and 4.38 (1H, dd, J 1.9, 10.0). Suggest a structure, assign the spectrum, and give a mechanism for the formation of B. H base C11H₂00 HBr B C11H₂1 Broarrow_forward
- A graduate student was making some 4-hydroxybutanoic acid and she obtained an excellent yield of a different compound whose 13C NMR is shown here. Propose a structure for this copound.arrow_forwardReaction of p-cresol with two equivalents of 2-methylprop-1-ene affords BHT, a preservative with molecular formula C15H24O. BHT gives the following 1H NMR spectral data: 1.4 (singlet, 18 H), 2.27 (singlet, 3 H), 5.0 (singlet, 1 H), and 7.0 (singlet, 2 H) ppm. What is the structure of BHT? Draw a stepwise mechanism illustrating how it is formed.arrow_forwardCompound A shows a molecular peak of 56 in Mass Spectrum. When compound A is treated with HBr and peroxides, it produces compound B, which shows twin molecular peaks with weights 136 and 138 in 1:1 ratio. The 'H NMR spectra of both compounds shown below. Identify the structures of A and B in the respective boxes. 2H Compound A 'H NMR of Compound A (integration is listed next to peaks) لد HBr peroxides 2H PPM 'H NMR of Compound B (integration is listed next to peaks, expansions in above) М 1H Compound B PPM 6H 6Harrow_forward
- (b) Reaction between an aldehyde and ketone (see below), in base gives a compound A with spectrum: 8 1.10 (9H, s), 1.17 (9H, s), 6,4 (1H. d. J 15 Hz), 7.0 (1H, d. J 15 Hz). What is its structure? When this compound reacts with HBr it gives compound B with this NMR spectrum: õ 1.08 (9H, s), 1.13 (9H, s), 2.71 (1H, dd, J 1.9 Hz, 17.7 Hz), 3.25 (1H, dd, J 10.0 Hz, 17.7 Hz), 4.38 (1H, dd, J 1.9 Hz, 10.0 Hz). Suggest a structure, assign the spectrum and give a mechanism for the formation of compound B. H. base HBr B C1H200 CH21Broarrow_forward8 8. Correlate each signal in the following 'H NMR for ethyl cinnamate with a particular set of hydrogens. Be sure to explain the location of the signal, the integration pattern, and the splitting pattern for all peaks. 'H NMR (300 MHz, DMSO): 1.21 (3H, t), 4.06 (2H, q), 6.31 (1H, d), 7.48 (1H, d), 7.33 (1H, t), 7.38 (2H, m), 7.54 (2H, d). 7 6 5 4 PPM 3 2 1 X 0arrow_forwardIdentify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?arrow_forward
- (b) One isomer of dimethoxybenzoic acid has 1H NMR spectrum dµ (ppm) 3.85 (6H, s), 6.63 (1H, t, J 2 Hz), and 7.17 (2H, d, J 2Hz), One isomer of coumalic acid has 'H NMR spectrum dн (ppm) 6.41 (1H, d, J 10 Hz), 7.82 (1H, dd, J 2 Hz, 10 Hz) and 8.51 (1H, d, J 2Hz). In each case, which isomer is represented here? The bonds sticking into the centre of the ring can be to any carbon atom. Note: COOH proton is not indicated in the spectra MeO HO₂C CO2H MeO dimethoxybenzoic acid coumalic acidarrow_forwardTreatment of butan-2-one (CH3COCH2CH3) with strong base followed byCH3I forms a compound Q, which gives a molecular ion in its massspectrum at 86. The IR (> 1500 cm−1 only) and 1H NMR spectra of Q aregiven below. What is the structure of Q?arrow_forwardIdentify products A and B from the given 1H NMR data. a.Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3 H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A? b.Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1 H) ppm. What is the structure of B?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning