In the given compounds A and B , the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified. Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 1

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Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 2

Question

Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 3

Question

Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 4

Question

Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 5

Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 6

Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 7

Chapter 14, Problem 14.13P

Interpretation Introduction

Interpretation: In the given compounds A and B, the compound that corresponds to dimethyl succinate and the one that corresponds to ethylene diacetate is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same groups of atoms are known as chemically equivalent protons. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 11

Ch. 14 - Problem 14.1 The NMR spectrum of recorded on a ...Ch. 14 - Prob. 14.2P Ch. 14 - How many NMR signals does each compound show? a....Ch. 14 - How many 1H NMR signals does each...Ch. 14 - How many 1H NMR signals does each compound give?...Ch. 14 - Label the protons in each highlighted CH2 group as...Ch. 14 - How many 1H NMR signals would you expect for each...Ch. 14 - Prob. 14.8P Ch. 14 - For each compound, first label each different type...Ch. 14 - Label each statement as True or False. a. When a...

Solution Summary: The author explains the structures of dimethyl succinate and ethylene diacetate.

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