Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 14, Problem 14.5P
To determine
Find the passive force
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Principles of Geotechnical Engineering (MindTap Course List)
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- In Figure 12.24, which shows a vertical retaining wall with a granular backfill, let H = 4 m, α = 17.5º, γ = 16.5 kN/m3, Φ' = 35º, and ẟ' = 10º. Based on Caquot and Kerisel’s solution, what would be the passive force per meter length of the wall?arrow_forwardPlease answer 13.21arrow_forwardA 6m retaining wall is supporting a soil with the following properties:Unit weight = 16 KN/cu.mAngle of internal friction = 25ºCohesion = 14 Kpaa. Assuming no tensile cracks occurs in the soil; determine its normal pressure acting at the back of the wall.b. If tensile crack occurs in the soil, calculate its active pressure acting on the wall.c. Find the location of tensile crack measured from the surface of horizontal backfill.arrow_forward
- 1- Figure below shows a retaining wall. Determine the magnitude of the lateral earth force per unit length for the following conditions: 1) At-rest force 2) Active force Also, find the location of the resultant, 7, measured from the bottom of the wall. H (ft) y (lb/ft') 15 19 120 Sand Unit weight = y (or density = p) %3D H c' = 0 8' (angle of wall friction) = 0arrow_forwardA frictionless retaining wall is shown ih the figure below. q= 10 kN/m 1= 15 kN/m o = 26° d'=8 kN/m 4 marrow_forward6. Details of a retaining wall are shown in the figure below. The unit weight of the wall material is 23 kN/m³. Assume a reduction factor K = 2/3 to consider the cohesion and friction angle at the base slab. Check the stability of the wall in terms of overturning and sliding failure. Use Rankine's theory to compute the active earth pressure. 6.5 m tu 1 2 m Yc = 23 kN/m³ 4 m -1.5m - Soil 2 Y2 = 17 kN/m³ ₂ = 10 kN/m² P2 = 25° a = 15⁰ Soil 1 Y₁ = 16 kN/m³ c₁ = 0 kN/m² 4₁ = 30°arrow_forward
- Use Eq. (12.3), Figure P12.2, and the following values to determine the at-rest lateral earth force per unit length of the wall. Also find the location of the resultant. H = 5 m, H1 = 2 m, H2 = 3 m, γ = 15.5 kN/m3, γsat = 18.5 kN/m3, Φ' = 34º, c' = 0, q = 20 kN/m2, and OCR = 1.arrow_forwardsxarrow_forward12.2 ), Figure P12.2, and the following values to determine the at-rest lat- eral earth force per unit length of the wall. Also find the location of the resultant. H = 5 m, H1 = 2 m, H, = 3 m, y = 15.5 kN/m², yt = 18.5 kN/m², 4' = 34°, c' = 0, q = 20 kN/m², . Repeat problem when water level Groundwater at ground surface. Figure P12.2arrow_forward
- 6. Details of a retaining wall are shown in the figure below. The unit weight of the wall 2/3 to consider the cohesion and material is 23 kN/m³. Assume a reduction factor K friction angle at the base slab. Check the stability of the wall in terms of overturning and sliding failure. Use Rankine's theory to compute the active earth pressure. 6.5 m m Ye= 23 kN/m³3 4 m -1.5m Soil 2 Y2 = 17 kN/m³ c₂ = 10 kN/m² 42 = 25° a = 15° Soil 1 Y₁ = 16 kN/m³ c₁ = 0 kN/m² 4₁ = 30°arrow_forward13.2 Assume that the retaining wall shown in Figure 13.9 is frictionless. Determine the Rankine active force per unit length of the wall, the variation of active earth pressure with depth, and the location of the resultant. If H = 4m, Ø = 36° and y = 18 kN/m3 kN Ans. P, = 37.44", z = 1.33m m 13.3 Assume that the retaining wall shown in Figure 13.9 is frictionless. Determine the Rankine passive force per unit length of the wall, the variation of lateral earth pressure with depth, and the location of the resultant. If H = 5m, Ø = 35° and y = 14 kN/m? Ans. Pp 645.8 kN z = 1.67m m. Sand Unit weight = y (or density = p) %3D H c' = 0 8' (angle of wall friction) = 0 Figure 13.9arrow_forward3. Draw the pressure diagram of the retaining wall with the soil profile shown both in active and passive cases. Solve for the active and passive lateral force and its location from the bottom of the wall. 4.5 KPa Gs = 2.73 e = 0.67 Ø = 27° C =0 KPa %3D 4m Gs = 2.66 %3D e = 0.85 Ø = 34° C = 5 KPa 6marrow_forward
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