The normal boiling point of the mercury has to be found. Concept introduction: At normal boiling point the liquid phase of any substance is in equilibrium with its gaseous phase. This means, the difference in free energy between the two phases is zero. Using this assumption the normal boiling point of mercury can be found. The equation given below helps us to calculate the change in free energy in a system. ΔG = Δ Η - T Δ S Entropy is the measure of randomness in the system. Entropy change in a reaction is the difference in entropy of theproducts and reactants. (ΔS) can be calculated by the following equation. ΔS rxn = S Products - S reactants Where, S reactants is the standard entropy of the reactants S Products is the standard entropy of the products Enthalpy is the amount energy absorbed or released in a process. The enthalpy change in a system (Δ Η sys ) can be calculated by the following equation. ΔH rxn = ΔH produdcts - ΔH reactants Where, ΔH reactants is the standard entropy of the reactants ΔH produdcts is the standard entropy of the products
The normal boiling point of the mercury has to be found. Concept introduction: At normal boiling point the liquid phase of any substance is in equilibrium with its gaseous phase. This means, the difference in free energy between the two phases is zero. Using this assumption the normal boiling point of mercury can be found. The equation given below helps us to calculate the change in free energy in a system. ΔG = Δ Η - T Δ S Entropy is the measure of randomness in the system. Entropy change in a reaction is the difference in entropy of theproducts and reactants. (ΔS) can be calculated by the following equation. ΔS rxn = S Products - S reactants Where, S reactants is the standard entropy of the reactants S Products is the standard entropy of the products Enthalpy is the amount energy absorbed or released in a process. The enthalpy change in a system (Δ Η sys ) can be calculated by the following equation. ΔH rxn = ΔH produdcts - ΔH reactants Where, ΔH reactants is the standard entropy of the reactants ΔH produdcts is the standard entropy of the products
Solution Summary: The author explains how the normal boiling point of mercury can be found. Entropy is the measure of randomness in the system.
The normal boiling point of the mercury has to be found.
Concept introduction:
At normal boiling point the liquid phase of any substance is in equilibrium with its gaseous phase. This means, the difference in free energy between the two phases is zero. Using this assumption the normal boiling point of mercury can be found.
The equation given below helps us to calculate the change in free energy in a system.
ΔG = ΔΗ- TΔS
Entropy is the measure of randomness in the system. Entropy change in a reaction is the difference in entropy of theproducts and reactants.
(ΔS) can be calculated by the following equation.
ΔSrxn = SProducts- Sreactants
Where,
Sreactants is the standard entropy of the reactants
SProducts is the standard entropy of the products
Enthalpy is the amount energy absorbed or released in a process.
The enthalpy change in a system
(ΔΗsys) can be calculated by the following equation.
ΔHrxn = ΔHprodudcts- ΔHreactants
Where,
ΔHreactants is the standard entropy of the reactants
ΔHprodudcts is the standard entropy of the products
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
+ More...
Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
The following equations represent the formation of compound MX. What is the AH for the
electron affinity of X (g)?
X₂ (g) → 2X (g)
M (s) → M (g)
M (g)
M (g) + e-
AH = 60 kJ/mol
AH = 22 kJ/mol
X (g) + e-X (g)
M* (g) +X (g) → MX (s)
AH = 118 kJ/mol
AH = ?
AH = -190 kJ/mol
AH = -100 kJ/mol
a)
-80 kJ
b)
-30 kJ
c)
-20 kJ
d)
20 kJ
e)
156 kJ
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