
Concept explainers
a.
Interpretation:
Fischer projection formula has to be drawn for the ball-and-stick model of the monosaccharide given and also it has to be labelled as D or L sugar.
Concept Introduction:
Fischer projection formula simply uses cross for representing tetrahedral carbon atom. The carbon atom that is present in the intersection point in cross. The horizontal bonds means they are coming forward and they are present on wedge bond. The vertical bonds means they are pointing away and they are present on dashed lines.
A carbon atom that is bonded to four different groups is known as a chiral carbon atom. This can rotate the plane polarized light. D- and L- isomers of monosaccharide can be identified by looking into the chiral center that is farther from the carbonyl group. In a Fischer projection, if the
b.
Interpretation:
Given monosaccharide has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.
Concept Introduction:
Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom
The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.
- Carbon chain with three carbon atoms is triose.
- Carbon chain with four carbon atoms is tetrose.
- Carbon chain with five carbon atoms is as pentose.
- Carbon chain with six carbon atoms is as hexose.

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Chapter 14 Solutions
Principles of General Organic & Biological Chemistry
- Michael Reactions 19.52 Draw the products from the following Michael addition reactions. 1. H&C CH (a) i 2. H₂O* (b) OEt (c) EtO H₂NEt (d) ΕΙΟ + 1. NaOEt 2. H₂O' H H 1. NaOEt 2. H₂O*arrow_forwardRank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic. НОН НЬ OHd Онсarrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? ? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C :0 T Add/Remove step Garrow_forward
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- Which one of the following atoms should have the largest electron affinity? a) b) c) d) 으으 e) 1s² 2s² 2p6 3s¹ 1s² 2s² 2p5 1s² 2s² 2p 3s² 3p² 1s² 2s 2p 3s² 3p6 4s2 3ds 1s² 2s² 2p6arrow_forwardAll of the following are allowed energy levels except _. a) 3f b) 1s c) 3d d) 5p e) 6sarrow_forwardA student wants to make the following product in good yield from a single transformation step, starting from benzene. Add any organic reagents the student is missing on the left-hand side of the arrow, and any addition reagents that are necessary above or below the arrow. If this product can't be made in good yield with a single transformation step, check the box below the drawing area. Note for advanced students: you may assume that an excess of benzene is used as part of the reaction conditions. : ☐ + I X This product can't be made in a single transformation step.arrow_forward
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