Chapter 14, Problem 14.26P

Interpretation Introduction

Interpretation:

Information interpreted about stability of $\text{LFe}\left(\text{III}\right)$ and $\text{LFe}\left(\text{II}\right)$ from the values of potential has to be given.

Concept Introduction:

Cell that is more negatively charge has better oxidation tendency and thus will readily lose electron. Electrons released from this electrode will reach the positive reduction potential electrode. For a general representation the oxidation half cell is drawn in left separated by double vertical parallel lines while reduction half cell comes at right.

Expression to compute $K_{\text{f}}$ from cell potential as per Nernst equation as follows:

  $K_{\text{f}}={10}^{n(E_{\text{cell}}^{°})/0.05916}$

Here,

$K_{\text{f}}$ denotes formation constant.

$E_{\text{cell}}^{°}$ denotes standard cell potential.

$n$ is the moles of electrons transferred.