Chapter 14, Problem 14.16P

Interpretation Introduction

Interpretation:

Solubility product of $\text{Mg}{\left(\text{OH}\right)}_{\text{2}}$ has to be calculated.

Concept Introduction:

Cell that is more negatively charge has better oxidation tendency and thus will readily lose electron. Electrons released from this electrode will reach the positive reduction potential electrode.

Expression to compute $K_{sp}$ from cell potential as per the Nernst equation as follows:

  $K_{\text{sp}}={10}^{n(E_{\text{cell}}^{°})/0.05916}$

Here,

$K_{\text{sp}}$ denotes solubility product

$E_{\text{cell}}^{°}$ denotes standard cell potential.

$n$ is the moles of electrons transferred.