Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 14, Problem 14.18CTP
(a)
To determine
Find the magnitude, location and direction of the resultant active force
(b)
To determine
Find the magnitude, location and direction of the resultant active force
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7.17 A soil profile consists of a clay layer underlain by a sand
layer, as shown in Figure P7.17 If a tube is inserted into
the bottom sand layer and the water level rises to 1 m
above the ground surface, determine the vertical effec-
tive stresses and porewater pressures at A, B, and C. If
K, is 0.5, determine the lateral effective and lateral total
stresses at A, B, and C. What is the value of the pore-
water pressure at A to cause the vertical effective stress
there to be zero?
GWL
|1 m Y- 18.5 kN/m
Clay
2m Yu- 19.0 kN/m
1.5 m Yur=17.0 kN/m
Sand
2m
E
Please answer 13.9
7.17 A soil profile consists of a clay layer underlain by a sand
layer, as shown in Figure P7.17. If a tube is inserted into
the bottom sand layer and the water level rises to 1 m
above the ground surface, determine the vertical effec-
tive stresses and porewater pressures at A, B, and C. If
K, is 0.5, determine the lateral effective and lateral total
stresses at A, B, and C. What is the value of the pore-
water pressure at A to cause the vertical effective stress
there to be zero?
GWL
11 m Y=18.5 kN/m?
Clay
2 m Y= 19.0 kN/m³
2: 1,5m Y =17.0 kN/m
Sand
2 m
FIGURE P7.17
Chapter 14 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
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- Situation 13. A river is 3 m deep with the riverbed consisting of a thick bed of sand having a saturated unit weight of 19.0 kN/m3³. Determine the resulting effective vertical stress at 4 m below the riverbed for the following conditions: 36. The water level stays the same. a. 36.80 kPa b. 47.20 kPa 37. The water level rises by 2 m. a. 51.1 kPa b. 36.80 kPa 38. The water level drops by 2 m. a. 26.30 kPa b. 36.80 kPa c. 26.30 kPa d. 51.10 kPa c. 47.20 kPa d. 26.30 kPa c. 47.20 kPa d. 51.10 kPa.arrow_forwardA retaining wall of height 10 m with clay backfill is shown in the figure (not to scale). Weight of the retaining wall is 5000 kN per m acting at 3.3 m from the toe of the retaining wall. The interface friction ER angle between base of the retaining wall and the base soil is 20. The depth of clay in front of the retaining wall is 2.0 m. The properties of the clay backfill and the clay placed in front of the retaining wall are the same. Assume that the tension crack is filled with water. Use Rankine's earth pressure theory. Take unit weight of water, Y = 9.81 kN/m³ Ywarrow_forwardExplanation it correctlyarrow_forward
- B A V = 130 kN 50 mm 150 mm 150 mm 150 mm 50 mm 150 mm www - Change the magnitude of the internal shear force from 130 kN to 90.2 kN Plot the intensity of the shear stress distribution acting over the cross-sectional area, and determine the resultant shear force developed in the vertical segment AB.arrow_forwardFor the frictionless wall retaining a stratified soil and shown in Fig. E3.2, determine: (a) The active lateral earth pressure distribution with depth. (b) The passive lateral earth pressure distribution with depth. (c) The magnitude and location of the active and passive forces. (d) The resultant force. (e) The ratio of passive moment to active moment. 4,- 20 kPa =250 %3D Ysen=20 kN/m =300 HAmarrow_forwardThe retaining wall shown above is subjected to an active earth pressure distribution as illustrsted in the figure. What is the eccentricity of the resultant load acting on this wall (measured from the centre of the wall)? XX w=240 kN/m 5m length W 2m 35 kPa O 0.31 m O 0.61 m O 0.23 m O 0.41 marrow_forward
- Determine the active lateral earth pressure on the frictionless wall shown in the figure below. Sketch the lateral earth pressure distributions and calculate the resultant force and its location from the base of the wall. Also, determine the moments of passive and active forces. Neglect seepage effects. Use Rankine's earth pressure method. (w = 10 kN/m) 3.0m Ysat 20 kN/m³ y = 19 kN/m²³ ' = 30° Ysat = 20 kN/m³ y = 18 kN/m³ o = 28 6.0marrow_forwardFor the frictionless wall shown in Figure No 1, Calculate the following: (a) The active lateral earth pressure distribution with depth. (b) The passive lateral earth pressure distribution with depth(c) The magnitudes and locations of the active and passive forces. (d) The resultant force and its location. (e) The ratio of passive moment to active moment. Note: UDL should be considered as mentioned in the figurearrow_forwardA retaining wall supports a horizontal backfill that is composed of two types of soil. The first layer is 4.79 meters high. It has a unit weight of 16.61 kN/m3. The second layer is 6.58 meters and has a unit weight of 18.72 kN/m3. If the angle of friction for both layers is 34°, determine the total active force (kN) acting on the retaining wall per unit width. Final answer should be in two decimal places.arrow_forward
- GEO NO. 5 SOLVE AND SHOW THE COMPLETE SOLUTION.arrow_forwardIt was found that the backfill against a retaining wall (6 meters in height as shown in Figure 3) has specify weight y= 16 kN/m³ when its water content w= 5 %, S = 0.12, its internal friction angle was measured as 30° (take G,= 2.7 and xw = 10 kN/m³). a. Predict distribution of lateral stress on this retaining wall along its depth in its “at rest" state, and its resultant force. b. Rain leads the backfill water content increase to 10% in its upper half, and saturated in its lower half, find and plot its lateral stress and pore pressures along its depth in an active state.arrow_forwardI need the complete answerarrow_forward
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