Chapter 13.5, Problem 34SPR

To determine

To determine probability of given event.

Answer to Problem 34SPR

P(pointer landing on blue) $=\frac{115}{360}=\frac{23}{72}\approx 0.3194$

Explanation of Solution

Given information:

  

Here we have to find P(pointer landing on blue)

To determine this we shall find the fraction of angle covered by the blue color on the spinner.

Hence the fraction of angle of blue color is $\frac{{115}^{\circ }}{{360}^{\circ }}$ (total angle of a circle is ${360}^{\circ }$ )

Now probability of the event will be same as the fraction of blue color as total possibilities of rotation of pointer can be 360 (considering for each degree)

Hence,

P(pointer landing on blue) $=\frac{115}{360}=\frac{23}{72}\approx 0.3194$