Chapter 13.3, Problem 13.3.3SR

Interpretation Introduction

Interpretation:

Molarity of $\text{0}\text{.258m}$ aqueous glucose solution has to be calculated.

Concept introduction:

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

$\text{Molarity (M) =}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{1}\text{liter}\text{of}\text{solution}}$

Molarity is estimation of moles in the total volume of the solution while molality is estimation of moles in relationship with solvent in the solution.