Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
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Chapter 13.2, Problem 1SB
You have a true-breeding strain of miniature-winged fruit flies, where this wing trait is recessive to the normal long wings. How would you show whether the miniature wing trait is sex-linked or autosomal?
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Consider a cross between a Brown furred dog and a Yellow furred dog. All the puppies born from these parents are yellow furred. Crossing the F1 yellow furred sons and F1 yellow furred daughters produces a 3:1 ratio of yellow furred dogs (3) to brown-furred dogs (1) in the F2 generation.
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Chapter 13 Solutions
Biology: The Dynamic Science (MindTap Course List)
Ch. 13.1 - You want to determine whether genes a and b are...Ch. 13.2 - You have a true-breeding strain of...Ch. 13.3 - What mechanisms are responsible for: (a)...Ch. 13.4 - A man has Simpson syndrome, an addiction to a...Ch. 13.4 - Prob. 2SBCh. 13.5 - Prob. 1SBCh. 13 - In humans, redgreen color blindness is an X-linked...Ch. 13 - The following pedigree shows the pattern of...Ch. 13 - Individuals affected by a condition known as...Ch. 13 - A number of genes carried on the same chromosome...
Ch. 13 - Prob. 5TYKCh. 13 - Discuss Concepts Can a linkage map be made for a...Ch. 13 - In Drosophila, two genes, one for body color and...Ch. 13 - Another gene in Drosophila determines wing length....Ch. 13 - Prob. 9TYKCh. 13 - You conduct a cross in Drosophila that produces...Ch. 13 - Discuss Concepts Crossing-over does not occur...Ch. 13 - Prob. 12TYKCh. 13 - Prob. 13TYKCh. 13 - Prob. 14TYKCh. 13 - Prob. 1ITDCh. 13 - Prob. 2ITDCh. 13 - Prob. 3ITDCh. 13 - Prob. 4ITD
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- Wild type fruit flies have grey bodies and straight wings. Yellow bodies and curly wings are both recessive phenotypes. The body color gene is X-linked; the wild type allele is designated XY+. The wing shape gene is autosomal; the wild type allele is designated C+. You cross a pure breeding yellow-bodied, curly-winged female with a grey-bodied, straight-winged male to produce an F1 generation. Use this information to answer questions X-Y below. 20) You cross two F1 flies to produce an F2 generation. What proportion of the F2 female flies are expected to have curly wings and yellow bodies? a) 1/16 b) 1/4 c) 1/8 d) 3/8 e) 3/16arrow_forwardIn Drosophila, the white gene located on the X chromosome affects eye color; an autosomal gene, wingless, is on an autosomal chromosome. Use the following allele symbols: Xw+ _ , Xw+Y = wild type red eyes; X-linked dominant allele Xw Xw , XwY = white eyes; X-linked recessive allele Y = Y sex chromosome vg+ = wild type wings; autosomal dominant vg = wingless; autosomal recessive Predict ratios/proportions of genotypes and phenotypes of offspring from the following cross, of a white-eyed male with wild type wings and a wild type red eyed female with wild type wings: indicate sex of offspring along with phenotypes. XwY vg+ vg x Xw+Xw vg+vgarrow_forwardPlease explain You are interested in the inheritance of two autosomal genes in a type of beetle. These genes determine carapace color (violet or green, governed by the alleles c+ and c) and presence or absence of a horn (with horn, without horn, determined by the alleles h+ and h). You cross two pure lines of beetles and let the F1 generation (c+/c · h+/h) intercross. The F2 progeny deviate from the expected Mendelian ratio, so you cross a dihybrid F1 female with a tester male. Of the 500 progeny, 132 are (c+ · h+), _____ are (c · h), 118 are (c · h+), and 110 are (c+ · h).arrow_forward
- Using the pedigree chart attached: Above is a pedigree for colorblindness. Based on the pedigree, is the disease dominant or recessive and is it sex-linked or autosomal? Why? Furthermore, what is the probability that 18 on this chart is affected but the condition, and what is the probability that 18 is a carrier? Why? Are the probability of being a carrier and an affected individual different? Why?arrow_forwardDraw a three-generation pedigree of an Autosomal Dominant family, with three children for every mating. Fill in the affected individuals. Then say, could your pedigree also be each of the following other types of pedigrees: Autosomal Recessive, X-Linked Dominant, X-linked recessive, Y-linked, and Mitochondrial. If it cannot be one of these patterns you must say why not and be VERY specific. If it can be, you can just say yes. autosomal dominant autosomal recessive x-linked dominant x-linked recessive y-linked mitochondrialarrow_forwardColor blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?arrow_forward
- The pedigree below shows a family with a history of an autosomal recessive genetic disease with one individual's genotype indicated (G denotes the normal allele and g denotes the disease-causing allele). * O 0 O 1/8 1/4 O 1/16 Individual 1's father is known to be heterozygous (*) and his mother is known to be homozygous dominant. Other individuals in the pedigree may be carriers, but are not marked. The question mark (?) indicates that you do not yet know anything about this individual's phenotype with regard to the disease. Part 1 What is the probability that individuals 1 and 2 will have a child (5) who is a male with the disease (the child is unborn and the sex is not yet known)? O 1/4 1 O 1/6 5 1/8 2 01/12 gg 3 Part 2 What is the probability that the daughter (female)(6) that individual 3 and 4 just had will have the disease? 6arrow_forwardThe following pedigree shows the pattern of inheritance of red-green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in black. What is the chance that a son of the third-generation female indicated by the arrow will be color blind if the father is not color blind? If he is color blind?arrow_forwardHemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?arrow_forward
- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardGiven the following pedigree: Is the trait autosomal or sex-linked? Is the trait dominant or recessive? Based only on the information given, what is the probability that I-2 is heterozygous? Give the genotypes of individuals II-3, II-4. What is the probability that individual III-1 is purebreeding?arrow_forwardThere are two genes in fruit flies that determine eye color and wing shape. Red eyes are dominant to sepia (brown) eyes, and normal wings is dominant to vestigial (shriveled) wings. Describe a procedure you could use to determine the genotype of a fly that has red eyes and normal wings. This fly may be homozygous or heterozygous for either gene.arrow_forward
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