
Concept explainers
Using the answers obtained in Prob. 13.108, show that the intended circular orbit and the resulting elliptic orbit intersect at the ends of the minor axis of the elliptic orbit.
13.108 A satellite is projected into space with a velocity v0 at a distance r0 from the center of the earth by the last stage of its launching rocket. The velocity v0 was designed to send the satellite into a circular orbit of radius r0. However, owing to a malfunction of control, the satellite is not projected horizontally but at an angle α with the horizontal and, as a result, is propelled into an elliptic orbit. Determine the maximum and minimum values of the distance from the center of the earth to the satellite.
Fig. P13.108

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Chapter 13 Solutions
Vector Mechanics for Engineers: Statics and Dynamics
- Problem 1. Two uniform rods AB and CE, each of weight 3 lb and length 2 ft, are welded to each other at their midpoints. Knowing that this assembly has an angular velocity of constant magnitude c = 12 rad/s, determine: (1). the magnitude and direction of the angular momentum HD of the assembly about D. (2). the dynamic reactions (ignore mg) at the bearings at A and B. 9 in. 3 in. 03 9 in. 3 in. Answers: HD = 0.162 i +0.184 j slug-ft²/s HG = 2.21 k Ay =-1.1 lb; Az = 0; By = 1.1 lb; B₂ = 0.arrow_forwardProblem 5 (Optional, extra 6 points) A 6-lb homogeneous disk of radius 3 in. spins as shown at the constant rate w₁ = 60 rad/s. The disk is supported by the fork-ended rod AB, which is welded to the vertical shaft CBD. The system is at rest when a couple Mo= (0.25ft-lb)j is applied to the shaft for 2 s and then removed. Determine the dynamic reactions at C and D before and after the couple has been removed at 2 s. 4 in. C B Mo 5 in 4 in. Note: 2 rotating around CD induced by Mo is NOT constant before Mo is removed. and ₂ (two unknowns) are related by the equation: ₂ =0+ w₂t 3 in. Partial Answer (after Mo has been removed): C-7.81+7.43k lb D -7.81 7.43 lbarrow_forwardProblem 4. A homogeneous disk with radius and mass m is mounted on an axle OG with length L and a negligible mass. The axle is pivoted at the fixed-point O, and the disk is constrained to roll on a horizontal surface. The disk rotates counterclockwise at the constant rate o₁ about the axle. (mg must be included into your calculation) (a). Calculate the linear velocity of G and indicate it on the figure. (b). Calculate ₂ (constant), which is the angular velocity of the axle OG around the vertical axis. (c). Calculate the linear acceleration ā of G and indicate it on the figure. (d). Determine the force (assumed vertical) exerted by the floor on the disk (e). Determine the reaction at the pivot O. 1 Answers: N = mg +mr(r/L)² @² |j mr w IIG C R L i+ 2L =arrow_forward
- Problem 2. The homogeneous disk of weight W = 6 lb rotates at the constant rate co₁ = 16 rad/s with respect to arm ABC, which is welded to a shaft DCE rotating at the constant rate 2 = 8 rad/s. Assume the rod weight is negligible compared to the disk. Determine the dynamic reactions at D and E (ignore mg). Answers: D=-7.12ĵ+4.47k lb r-8 in. 9 in. B D E=-1.822+4.47 lb 9 in. E 12 in. 12 in. xarrow_forwardProblem 3. Each of the right angle rods has a mass of 120 g and is welded to the shaft, which rotates at a steady speed of 3600 rpm. Ignore the weight of the shaft AB. Find the bearing dynamic reaction at A due to the dynamic imbalance of the shaft. (ignore mgs) 100 N A 100 100 100 100 100 (Dimensions in millimeters) Answer: A=-8521-426j N Barrow_forwardThermodynamics. Need help solving this. Step by step with unitsarrow_forward
- Quiz/An eccentrically loaded bracket is welded to the support as shown in Figure below. The load is static. The weld size for weld w1 is h1 = 4mm, for w2 h2=6mm, and for w3 is h3 -6.5 mm. Determine the safety factor (S.f) for the welds. F=29 kN. Use an AWS Electrode type (E100xx). 163 mm 133 mm 140 mm w3 wiarrow_forwardE W X FO FB F10 F11 F12 Home Q: Consider the square of Figure below.The left face is maintained at 100°C and the top face at 500°C, while the other two faces are exposed to an environment at1 00°C, h=10 W/m². C and k=10 W/m.°C. The block is 1 m square. Compute the temperature of the various nodes as indicated in Figure below and the heat flows at the boundaries. T= 500°C Alt Explain to me in detail how to calculate the matrix in the Casio calculator type (fx-991ES plus) T= 100°C 1 2 4 7 1 m- 3 1 m 5 6 T= 100°C 8 9arrow_forwardWhich of the following sequences converge and which diverge? 1) a₁ = 2+(0.1)" 1-2n 2) a = 1+2n 1/n 3 16) a = n In n 17) an = n 1/n 1-5n4 3) an = n² +8n³ 18) an = √4" n n² -2n+1 n! 20) a = 4) an = 106 5) n-1 a₁ =1+(-1)" n+1 a-(+) (1-4) 6) = 7) a = 2n (-1)"+1 2n-1 21) an = n -A" 1/(Inn) 3n+1 22) a = 3n-1 1/n x" 23) a = , x>0 2n+1 3" x 6" 24) a = 2™" xn! 2n 8) a = n+1 πT 1 9) a„ = sin +- 2 n sin n 10) an = n 25) a = tanh(n) 26) a = 2n-1 27) a = tan(n) 1 -sin n n 11) a = 2" 28) an == " 1 + 2" In(n+1) 12) a = n (In n) 200 29) a = n 13) a = 8/n 14) a 1+ =(1+²)" 15) an 7 n = 10n 30) an-√√n²-n 1"1 31) adx nixarrow_forward
- A steel alloy contains 95.7 wt% Fe, 4.0 wt% W, and 0.3 wt% C.arrow_forwardb. A horizontal cantilever of effective length 3a, carries two concentrated loads W at a distance a from the fixed end and W' at a distance a from the free end. Obtain a formula for the maximum deflection due to this loading using Mohr's method. If the cantilever is 250 mm by 150mm steel I beam, 3 m long having a second moment of area I as 8500 cm4, determine W and W'to give a maximum deflection of 6 mm when the maximum stress due to bending is 90 Mpa. Take Young's modulus of material E as 185 Gpa.arrow_forwardWhich of the following sequences converge and which diverge? 1/n 1) a₁ = 2+(0.1)" 3 16) a = n 1-2n 2) a = In n 1+2n 17) an = 1/n n 1-5n4 3) an = n² +8n³ 18) an = √4" n n! n² -2n+1 20) a = 4) an = 106 5) n-1 a₁ =1+(-1)" n+1 a-(+) (1-4) 6) = 7) a = 2n (-1)"+1 2n-1 21) an = n -A" 1/(Inn) 3n+1 22) a = 3n-1 1/n x" 23) a = , x>0 2n+1 3" x 6" 24) a = 2™" xn! 2n 8) a = n+1 πT 1 9) a„ = sin +- 2 n sin n 10) an = n 25) a = tanh(n) 26) a = 2n-1 27) a = tan(n) 1 -sin n n 11) a = 2" 28) an == " 1 + 2" In(n+1) 12) a = n (In n) 200 29) a = n 13) a = 8/n 14) a 1+ =(1+²)" 15) an 7 n = 10n 30) an-√√n²-n 1"1 31) adx nixarrow_forward
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